Question

以下解决方案收到错误的输出：http://prntscr.com/atfm5w

int main() 
{
int n;
int f = 1;
cout << "Enter an integer: ";
cin >> n;

for (int i = 1; i <= n; i++)   // 1st loop to get list of numbers from 1-n.
{
    cout << "| " << i << ": ";
    while (f <= i) {      // 2nd loop to get list of factors for each number from 1-n

        if (i%f == 0)     // divisibility check
        {
            cout << f;
        }
        f++;
    }
    cout << endl;
}

我已经黑了近一个小时了，我不再理解这段代码的逻辑了。如果有人能够解决这个问题或者向我解释有缺陷的代码的逻辑，我将非常感激，所以我可以解决它。

Answer 1

您需要为每个号码重新初始化值f=1：

int main() 
{
    int n;
    int f = 1;
    cout << "Enter an integer: ";
    cin >> n;

    for (int i = 1; i <= n; i++)
    {
        f=1;                          //   reinitialize
        cout << "| " << i << ": ";
        while (f <= i) {
        if (i%f == 0)
        {
            cout << f;
        }
        f++;
        }
        cout<<"\n";
    }
    cout << endl;
}

https://ideone.com/KvFFDf

使用双循环分解数字

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