我正在尝试使用three.js
我正在使用补间移动相机,效果非常好。 但是,在动画结束时,相机会跳回到初始位置。
我发现mousemove事件导致了这种行为。 如何解决此问题并保持补间动作和鼠标移动?
我根据this example构建了我的three.js;
在渲染功能中声明了Mousemove
function render() {
camera.position.x += ( mouseX - camera.position.x ) * 0.04;
camera.position.y += ( - mouseY - camera.position.y ) * 0.04;
camera.lookAt( scene.position );
TWEEN.update();
renderer.render( scene, camera );
}
补间动作
function setupTween (position, target, duration) {
TWEEN.removeAll();
new TWEEN.Tween (position)
.to (target, duration)
.easing (TWEEN.Easing.Quadratic.InOut)
.onUpdate (
function() {
// copy incoming position into camera position
camera.position.copy (position);
})
.start();
};
更新
完整的工作代码:
<script>
var container,
i,
camera,
scene,
renderer,
particles,
geometry,
materials = [],
color,
sprite,
size,
mouseX = 0,
mouseY = 0,
isTweening,
windowHalfX = window.innerWidth / 2,
windowHalfY = window.innerHeight / 2;
// +++++ three.js +++++
// +++++ +++++ +++++ +++++ +++++
function init() {
container = document.createElement( 'div' );
document.body.appendChild( container );
camera = new THREE.PerspectiveCamera(45, window.innerWidth / window.innerHeight, 0.5, 2000 );
camera.position.set (0,0,1900);
scene = new THREE.Scene();
scene.fog = new THREE.FogExp2( 0x000000, 0.0005 );
geometry = new THREE.Geometry();
var textureLoader = new THREE.TextureLoader();
for ( i = 0; i < 1000; i ++ ) {
var vertex = new THREE.Vector3();
vertex.x = Math.random() * 2000 - 1000;
vertex.y = Math.random() * 2000 - 1000;
vertex.z = Math.random() * 2000 - 1000;
geometry.vertices.push( vertex );
}
sprite = textureLoader.load( "circle.png" );
color = [0.90, 0.05, 0.8];
size = 8.5;
materials = new THREE.PointsMaterial( { size: size, map: sprite, blending: THREE.AdditiveBlending, depthTest: false, transparent : false } );
materials.color.setHSL( color[0], color[1], color[2] );
particles = new THREE.Points( geometry, materials );
scene.add( particles );
renderer = new THREE.WebGLRenderer({ antialias: true, alpha: true });
renderer.setPixelRatio( window.devicePixelRatio );
renderer.setSize( window.innerWidth, window.innerHeight );
container.appendChild( renderer.domElement );
document.addEventListener( 'mousemove', onDocumentMouseMove, false );
}
function onWindowResize() {
windowHalfX = window.innerWidth / 2;
windowHalfY = window.innerHeight / 2;
camera.aspect = window.innerWidth / window.innerHeight;
camera.updateProjectionMatrix();
renderer.setSize( window.innerWidth, window.innerHeight );
}
function onDocumentMouseMove( event ) {
mouseX = event.clientX - windowHalfX;
mouseY = event.clientY - windowHalfY;
}
function animate() {
requestAnimationFrame( animate );
render();
}
function startTween() {
isTweening = false;
var target = new THREE.Vector3(getRandomNumber(), getRandomNumber(), getRandomNumber());
new TWEEN.Tween (camera.position.clone())
.to (target, 1000)
.easing (TWEEN.Easing.Quadratic.InOut)
.onUpdate( function() {
camera.position.copy(this);
})
.onStart ( function() {
isTweening = true;
})
.onComplete ( function() {
isTweening = false;
})
.start();
}
function getRandomNumber() {
// get a number between -1000 and -500 and 500 and 1000
return ( Math.random() * 500 + 500 ) * ( Math.random() < 0.5 ? -1 : 1 );
}
function render() {
if(!isTweening && (mouseX || mouseY)) {
// more a generic approach, not just transforming x and y (maybe it needs to be improved a bit)
var upVector = camera.up.clone().transformDirection(camera.matrix);
var forwardVector = new THREE.Vector3().subVectors(scene.position, camera.position).normalize();
var rightVector = new THREE.Vector3().crossVectors(forwardVector, upVector);
camera.translateOnAxis(rightVector, mouseX);
camera.translateOnAxis(upVector, -mouseY);
mouseX = mouseY = 0;
}
camera.lookAt( scene.position );
TWEEN.update();
renderer.render( scene, camera );
}
init();
animate();
setTimeout(function(){
startTween();
},2500);
</script>
答案 0 :(得分:0)
我认为,只有当它没有补间时,你应该只通过mousemove事件更新位置。所以你需要检查它当前是否补间。
var isTweening = false;
new TWEEN.Tween (camera.position)
.to (target, duration)
.easing (TWEEN.Easing.Quadratic.InOut)
.onStart ( function() {
isTweening = true;
})
.onComplete ( function() {
isTweening = false;
})
.start();
// in your render loop
function render() {
if (!isTweening) {
camera.position.x += ( mouseX - camera.position.x ) * 0.04;
camera.position.y += ( - mouseY - camera.position.y ) * 0.04;
}
camera.lookAt( scene.position );
TWEEN.update();
renderer.render( scene, camera );
}
您无需设置onUpdate
功能并将新位置复制到camera.position
。您可以将camera.position
传递给补间,它可以正常工作。
修改强>
我没有看到示例的链接。现在,我知道使用了哪种导航(实际上在很多三个例子中都使用了这种导航)。这不是导致问题的mousemove事件,而是计算新摄像机位置(camera.position.x += ( mouseX - camera.position.x ) * 0.04;
)。所以,我稍微更改了示例的代码,尤其是导航。以下是重要部分:
document.addEventListener( 'mousemove', onDocumentMouseMove, false );
function onDocumentMouseMove( event ) {
mouseX = (event.movementX * 0.5) || event.mozMovementX || event.webkitMovementX || 0;
mouseY = (event.movementY * 0.5) || event.mozMovementY || event.webkitMovementY || 0;
}
function render() {
if(!isTweening && (mouseX || mouseY)) {
// more a generic approach, not just transforming x and y (maybe it needs to be improved a bit)
var upVector = camera.up.clone().transformDirection(camera.matrix);
var forwardVector = new THREE.Vector3().subVectors(scene.position, camera.position).normalize();
var rightVector = new THREE.Vector3().crossVectors(forwardVector, upVector);
camera.translateOnAxis(rightVector, mouseX);
camera.translateOnAxis(upVector, -mouseY);
mouseX = mouseY = 0;
}
camera.lookAt( scene.position );
TWEEN.update();
}
function startTween() {
isTweening = false;
var target = new THREE.Vector3(getRandomNumber(), getRandomNumber(), getRandomNumber());
new TWEEN.Tween (camera.position.clone())
.to (target, 1000)
.easing (TWEEN.Easing.Quadratic.InOut)
.onUpdate( function() {
camera.position.copy(this);
})
.onStart ( function() {
isTweening = true;
})
.onComplete ( function() {
isTweening = false;
})
.start();
}
function getRandomNumber() {
// get a number between -1000 and -500 and 500 and 1000
return ( Math.random() * 500 + 500 ) * ( Math.random() < 0.5 ? -1 : 1 );
}
您对TWEEN.onUpdate
的看法是正确的:您需要将新值复制到camera.position
。我之前的方法也有效,但THREE.Vector3
的所有功能都会丢失。直到现在我才意识到这一点。