目前，我正在使用类似的东西将JSON内容（def create
@casting = Casting.new(casting_params)
@casting.models_booked = 0
@casting.save
link = LinkModelAndCasting.new
link.client_id = @casting.id
link.save
# link_model_and_casting = LinkModelAndCasting.new(:casting_id => @casting.id)
# link_model_and_casting.save
respond_to do |format|
if @casting.id
format.html { redirect_to @casting, notice: 'Casting was successfully created.' }
format.json { render :show, status: :created, location: @casting }
else
format.html { render :new }
format.json { render json: @casting.errors, status: :unprocessable_entity }
end
end
end
）写入文件（my_json）：
my_output_filepath这很有效，但我想知道是否有必要将import Data.Aeson.Encode.Pretty
import qualified Data.ByteString.Lazy.UTF8 as U
writeFile my_output_filepath $ U.toString $ encodePretty my_json
返回的ByteString转换为encodePretty，然后再将其写入文件，或者如果它导致性能损失。
我看到String的{{3}}接受writeFile作为输入。但是，当我尝试使用它时，我收到此错误：
ByteString是否有某种方法可以使Couldn't match expected type ‘B.ByteString’
with actual type ‘U.ByteString’
NB: ‘B.ByteString’ is defined in ‘Data.ByteString.Internal’
‘U.ByteString’ is defined in ‘Data.ByteString.Lazy.Internal’
Lazy变体与ByteString互操作？