Question

我在下面放置一个代码，我已经创建了一个本地线程并在最后一个关闭大括号中获得错误，任何人都可以帮我解决一下。

Thread dt = new Thread(this){
public void run() 
    {
        Looper.prepare();
        GetCurrentLocation loc = new GetCurrentLocation(RestaurantFinder.this);
        loc.setLocParams();

        int counter = 0;
        String lat = GetCurrentLocation.getCurrentLatitude();
        String lon = GetCurrentLocation.getCurrentLongitude();

        while (lat == null && lon == null
                && counter <= 1000) 
        {
            lat = GetCurrentLocation.getCurrentLatitude();
            lon = GetCurrentLocation.getCurrentLongitude();
            counter = counter + 1;
        }

        System.out.println("The Latitude are:" + lat);
        System.out.println("The Longitude are:"+ lon);

        if (lat == null && lon == null) 
    {
            // another alert for location not found

            AlertDialog.Builder builder1 = new AlertDialog.Builder(RestaurantFinder.this);
            builder1.setTitle("Restaurant Finder");
            builder1.setMessage("Unable to find the Current Location");
            builder1.setPositiveButton("OK",new DialogInterface.OnClickListener()
            {

                                @Override
                                public void onClick(DialogInterface dialog,int which) 
                                {


                                    dialog.dismiss();

                                }
            });

            AlertDialog dialog1 = builder1.create();
            dialog1.show();

            // dismiss ProgressDialog by Handler
            pd.dismiss();

        } 
        else
        {

            weather();
            // dismiss ProgressDialog by Handler
            pd.dismiss();
        }

    }

});<--(Error:Syntax error on token ")", Delete this token)

Answer 1

如果你正确缩进代码，那么这样的问题会更容易被发现。

如果我正确匹配大括号，我认为应该通过简单地删除)字符来解决直接问题（语法错误）。

但是，匿名线程类实例化中的this参数确实存在疑问：

如果你想传递这样的参数，你需要在你的匿名内部类中使用相应的构造函数。
看起来this可能是Runnable的一个实例。如果是这样，那么覆盖run Thread方法会失败通过构造函数传递Runnable的目的。
通常认为对Thread类进行子类化是一个坏主意。

我认为你的代码应该是这样的：

Thread dt = new Thread(new Runnable() {
     public void run() {
         ...
     }
});

...这可能解释了为什么你在那里有额外的) !!

如果this确实是Runnable你可以写：

Thread dt = new Thread(this);

Answer 2

LOL ......正如错误所示：删除此令牌，所以这样做：

Thread dt = new Thread(this){
public void run() 
    {
        Looper.prepare();
        GetCurrentLocation loc = new GetCurrentLocation(RestaurantFinder.this);
        loc.setLocParams();

        int counter = 0;
        String lat = GetCurrentLocation.getCurrentLatitude();
        String lon = GetCurrentLocation.getCurrentLongitude();

        while (lat == null && lon == null
                && counter <= 1000) 
        {
            lat = GetCurrentLocation.getCurrentLatitude();
            lon = GetCurrentLocation.getCurrentLongitude();
            counter = counter + 1;
        }

        System.out.println("The Latitude are:" + lat);
        System.out.println("The Longitude are:"+ lon);

        if (lat == null && lon == null) 
    {
            // another alert for location not found

            AlertDialog.Builder builder1 = new AlertDialog.Builder(RestaurantFinder.this);
            builder1.setTitle("Restaurant Finder");
            builder1.setMessage("Unable to find the Current Location");
            builder1.setPositiveButton("OK",new DialogInterface.OnClickListener()
            {

                                @Override
                                public void onClick(DialogInterface dialog,int which) 
                                {


                                    dialog.dismiss();

                                }
            });

            AlertDialog dialog1 = builder1.create();
            dialog1.show();

            // dismiss ProgressDialog by Handler
            pd.dismiss();

        } 
        else
        {

            weather();
            // dismiss ProgressDialog by Handler
            pd.dismiss();
        }

    }
};

需要找到线程错误

2 个答案: