这是我的代码:
extends ../layout
block content
-
projects = [ { "name": "testProject", "status": "Active", "github": "", "slack": "", "trello", "" }, { "name": "testProject", "status": "Active", "github": "", "slack": "", "trello", "" } ]
div.container
// Nav tabs
ul.nav.nav-tabs(role='tablist')
li.active(role='presentation')
a(href='#active', aria-controls='active', role='tab', data-toggle='tab') Active
li(role='presentation')
a(href='#inactive', aria-controls='inactive', role='tab', data-toggle='tab') Inactive
// Tab panes
.tab-content
#active.tab-pane.active(role='tabpanel')
each project in projects
#projects
.media
.media-left
i.fa.fa-2x.fa-code.media-object
.media-body
h4.media-heading #{project.name}
span.label.label-success #{project.status}
span.label.label-warning Help Wanted
.links
span.github
i.fa.fa-code-fork
a(href='#{project.github}') GitHub
span.slack
i.fa.fa-slack
a(href='#{project.slack}') Slack
span.trello
i.fa.fa-trello
a(href='#{project.trello}') Trello
我需要迭代数组中的每个对象并使用jade显示每个对象。我不知道该怎么办! 我按照这些教程:
http://jade-lang.com/reference/code/ iterate over an array of objects in jade/pugjs
答案 0 :(得分:2)
您的 JSON 对象似乎有点不对......试试这个
您的Json看起来像" trello","" 将其更改为" trello":&# 34;" 强> 这将验证您的json对象,以便它可以在每个循环的玉器中工作。
以下是一个例子:
projects = [
{
"name": "testProject",
"status": "Active",
"github": "",
"slack": "",
"trello": ""
},
{
"name": "testProject",
"status": "Active",
"github": "",
"slack": "",
"trello": ""
} ]
只需将下方复制并复制到您的文件中就可以了!
projects = [ { "name": "testProject", "status": "Active", "github": "", "slack": "", "trello": "" }, { "name": "testProject", "status": "Active", "github": "", "slack": "", "trello": "" } ]
答案 1 :(得分:0)
使用=
符号访问属性:
-var projects = [{name: 'name1', link: "link1"}, {name: 'name2', link: 'link2'}]
each project in projects
div
a(href=project.link)= project.name
如果要将变量插入字符串,请使用#{var}
表示法:
a(href='my-link-#{project.link}')= project.name