Question

我有一个阵列。如何比较3到3的值，如果有3个重复，则删除？

这是我尝试但不起作用。

$arr = array("bmw","white","class A", "mazda","red","demio", "Honda","maroon","vezel", "bmw","white","class A");
$chunks = array_chunk($arr,3);
$finalArr = array_unique( $chunks );

这是我在上面尝试做的一个例子：

//original array
$arr = ("bmw","white","class A", "mazda","maroon","class A", "Honda","maroon","vezel", "bmw","white","class A");

//separated array values to 3 by 3 sets
 "bmw",   "white",   "class A"
 "mazda", "maroon",  "class A"
 "Honda", "maroon",  "vezel"
 "bmw",   "white",   "class A"

//Removing 3set duplicates and expected new array:
$finalArr = ("bmw","white","class A", "mazda","maroon","class A", "Honda","maroon","vezel");

我正在寻找一种方法来删除块重复（3个匹配集）。没有重复。

Answer 1

使用array_map，implode和explode函数的解决方案：

$arr = array("bmw","white","class A", "mazda","red","demio", "Honda","maroon","vezel", "bmw","white","class A");
$chunks = array_chunk($arr,3);
$uniqueArr = array_unique(array_map(function($v){ return implode(",",$v);  },$chunks));
$finalArr = array_map(function($v){ return explode(",",$v);  },$uniqueArr);

print_r($finalArr);

输出：

Array
(
    [0] => Array
        (
            [0] => bmw
            [1] => white
            [2] => class A
        )

    [1] => Array
        (
            [0] => mazda
            [1] => red
            [2] => demio
        )

    [2] => Array
        (
            [0] => Honda
            [1] => maroon
            [2] => vezel
        )
)

array_unique（）首先对作为字符串处理的值进行排序，然后保留每个值遇到的第一个键，并忽略所有值以下钥匙。

Answer 2

我认为重点是找到一个＆＃34;对象＆＃34;使array_unique有效，类型＆＃34;数组＆＃34;似乎不合适。类型＆＃34;字符串＆＃34;应该适合，我会尝试这样的事情：

$a0 = array_chunk($arr,3);
//
$a1 = array();
foreach ($a0 as $r) $a1[]= implode('_', $r);
//
$a2 = array_unique($a1);
//
$final = array();
foreach ($a2 as $r) $final[]= explode('_', $r);

缺点：你必须确保任何原始字符串中都没有_ ......

使用array_chunk（）分隔数组并删除chunk duplicates

2 个答案: