Question

我的数组看起来像这样，

Array
(
  [0] => Array
      (
          [id] => 224983
          [name] => James
          [weight] => 0
          [bank] => Bank A
          [transaction] => 1
          [total] => 7682000000
          [reference] => Edward
          [type] => BRANCH
          [reference_id] => 222818
          [account_number] => 1220007355285
      )
  [1] => Array
      (
          [id] => 224984
          [name] => James
          [weight] => 0
          [bank] => Bank A
          [transaction] => 1
          [total] => 7682000000
          [reference] => Edward
          [type] => BRANCH
          [reference_id] => 222819
          [account_number] => 1220007355285
      )
  [3] => Array
      (
          [id] => 224985
          [name] => Maria
          [weight] => 0
          [bank] => Bank B
          [transaction] => 1
          [total] => 1500000000
          [reference] => Andrey
          [type] => BRANCH
          [reference_id] => 247620
          [account_number] => 1220000412901
      )              
)

当account_number，reference和name相同时，我想删除另一个，并根据id保留最后一个...

请有人帮我查一下，我已经被困在这里，所以输出将是[＆＃39; id] =＆gt;删除数组[0] 224983，其余数组将是结果

Answer 1

尝试以下功能，这将有助于删除重复的数组。

function array_unique_multidimensional($input)
{
    $serialized = array_map('serialize', $input);
    $unique = array_unique($serialized);
    return array_intersect_key($input, $unique);
}

Answer 2

如果您只是想比较数组中的三个字段，那么您可以尝试以下方式。哪些检查重复和未设置以前的条目。这里$ data是数组输入

foreach ($data as $key => $row) {
    $id   = $row['id'];
    $name = $row['name'];
    $reference = $row['reference'];

    $flag = 0;
    for($i = $key + 1; $i < count($data); $i++)
    {
        if(($data[$i]['id'] == $id) && ($data[$i]['name'] == $name) && ($data[$i]['reference'] == $reference))
        {
            if($key != $i)
                unset($data[$key]);
        }
    }
}

结果将是

Array
(
    [1] => Array
        (
            [id] => 224983
            [name] => James
            [weight] => 0
            [bank] => Bank A
            [transaction] => 1
            [total] => 7682000000
            [reference] => Edward
            [type] => BRANCH
            [reference_id] => 222818
            [account_number] => 1220007355285
        )

    [2] => Array
        (
            [id] => 224985
            [name] => Maria
            [weight] => 0
            [bank] => Bank B
            [transaction] => 1
            [total] => 1500000000
            [reference] => Andrey
            [type] => BRANCH
            [reference_id] => 247620
            [account_number] => 1220000412901
        )

)

Answer 3

它似乎不优雅，但我认为您需要遍历以前的数组元素来检查ID。你可以创建一个像这样的函数：

function id_exists_prior(&$my_array, $array_index) {
    for($i = 0; $i < $array_index; $i++) {
        if($my_array[$i]['id'] === $my_array[$array_index]['id']) return false;
    }
    return true;
}

然后你可以在你想要的任何数组元素上调用它，或者循环遍历整个数组以检查重复项。后者的一个例子：

$your_array = [/*Your array data*/];
for($key = 0; $key < count($your_array); $key++) { 
    if(id_exists_prior($your_array, $key)) //Do your thing
}

将数组键传递给函数的原因是，函数只检查先前的重复项。

希望这有帮助！

删除重复数组

3 个答案: