Question

我正在使用UserType 3.2.0-GA，Hibernate 4.3.8，与AWS（RDS）上现有的mysql实例交谈。

我正在尝试从Hibernate 3.2.6和joda-time-hibernate 1.1升级应用程序。

失败的财产：

import org.joda.time.LocalDate; ... public LocalDate getBirthdate() { return this.birthdate; }

模特：

org.hibernate.type.SerializationException: could not deserialize (Caused by: java.io.StreamCorruptedException: invalid stream header: 31393936)
org.hibernate.internal.util.SerializationHelper.doDeserialize(SerializationHelper.java:262)
org.hibernate.internal.util.SerializationHelper.deserialize(SerializationHelper.java:306)
org.hibernate.type.descriptor.java.SerializableTypeDescriptor.fromBytes(SerializableTypeDescriptor.java:155)
org.hibernate.type.descriptor.java.SerializableTypeDescriptor.wrap(SerializableTypeDescriptor.java:130)
org.hibernate.type.descriptor.java.SerializableTypeDescriptor.wrap(SerializableTypeDescriptor.java:44)
org.hibernate.type.descriptor.sql.VarbinaryTypeDescriptor$2.doExtract(VarbinaryTypeDescriptor.java:71)
org.hibernate.type.descriptor.sql.BasicExtractor.extract(BasicExtractor.java:64)
org.hibernate.type.AbstractStandardBasicType.nullSafeGet(AbstractStandardBasicType.java:267)
org.hibernate.type.AbstractStandardBasicType.nullSafeGet(AbstractStandardBasicType.java:263)
org.hibernate.type.AbstractStandardBasicType.nullSafeGet(AbstractStandardBasicType.java:253)
org.hibernate.type.AbstractStandardBasicType.hydrate(AbstractStandardBasicType.java:338)
...
java.io.ObjectInputStream.readStreamHeader(ObjectInputStream.java:804)

尝试读取现有数据时出错：

WARN: SQL Error: 1292, SQLState: 22001
Apr 12, 2016 5:12:07 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: Data truncation: Incorrect date value: 'ï¿½ï¿½' for column 'birthdate' at row 1
Apr 12, 2016 5:12:07 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper$StandardWarningHandler logWarning
WARN: SQL Warning Code: 1292, SQLState: HY000
Apr 12, 2016 5:12:07 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper$StandardWarningHandler logWarning
WARN: Incorrect date value: 'ï¿½ï¿½' for column 'birthdate' at row 1

尝试写入新数据时出错：

org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; nested exception is org.hibernate.exception.DataException: could not execute statement

<bean id="hibernateProperties" class="org.springframework.beans.factory.config.PropertiesFactoryBean"> <property name="properties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQL5InnoDBDialect</prop> <prop key="hibernate.hbm2ddl.auto">update</prop> <prop key="hibernate.generate_statistics">true</prop> <prop key="hibernate.cache.region.factory_class">org.hibernate.cache.EhCacheRegionFactory</prop> <prop key="hibernate.cache.provider_class">org.hibernate.cache.EhCacheProvider</prop> <prop key="hibernate.cache.use_query_cache">true</prop> <prop key="jadira.usertype.autoRegisterUserTypes">true</prop> </props> </property> </bean>

正如您所看到的，我正在使用Spring来配置内容。我在春天的hibernate属性是：

<body>
<S1 A="1">
    <S2 B="1">
        <S3 C="1"/>
        <S3 C="1"/>
    </S2>
    <S2 B="2"/>
</S1>
<S1 A="2"/>

Answer 1

原来我通过将类型设置为：

来实现它

<property name="birthdate" not-null="true" type="org.jadira.usertype.dateandtime.joda.PersistentLocalDate"/>

不幸的是，我不明白为什么这样做或者甚至是必要的。更多的解释会很棒。

Hibernate无法读取或写入org.joda.time.LocalDate

1 个答案: