Question

当我想从valise，表视图控制器（SelectedCity），应用程序崩溃和错误中创建数据时：Thread1：EXC_BAD_ACCESS（代码= 1，地址0x ...）错误是行For i = 0 To 10 Try 'System.IO.File.Delete(sFileName) 'My.Computer.FileSystem.DeleteFile(sFileName, FileIO.UIOption.OnlyErrorDialogs, FileIO.RecycleOption.DeletePermanently) My.Computer.FileSystem.DeleteFile(sFileName) Exit For Catch ex As Exception If i = 10 Then invioMailTest(ex.ToString) End If Threading.Thread.Sleep(1000) End Try Next varibale tit没问题，我认为问题出在UIlabel（labelcity）

你可以帮帮我吗？

AircraftSearch

labelcity!.text = tit

SelectedCity视图

class AircraftSearch: UIViewController ,SendbackDelegate{

    @IBOutlet weak var Mabda: UIButton!
    @IBOutlet weak var maghsad: UIButton!
    @IBOutlet weak var labelcity: UILabel!


    var Airurl = NSURL()
    var ScrOrDstArray = [MabdaAndMaghsad]()
    var origin = [String]() // save mabda
    var purpose = [String]() // save maghsad
    var sendDataToTableview = [String]()
    var tit = String()


    override func viewWillAppear(animated: Bool) {
        super.viewWillAppear(animated)

        navigationController?.setNavigationBarHidden(false, animated: true)
    }


    override func viewDidLoad() {
        super.viewDidLoad()
        GetPassCity()

    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    @IBAction func selectMabda(sender: AnyObject) {
        sendDataToTableview = origin
        performSegueWithIdentifier("SelectedCellSegue", sender: sender)


    }

    @IBAction func selectMaghsad(sender: AnyObject) {
        sendDataToTableview = purpose
        print(sendDataToTableview)
        performSegueWithIdentifier("SelectedCellSegue", sender: sender)

    }


    func originAndpurpose() {
        let dataCity = ScrOrDstArray
        for i in dataCity{

            if i.SrcOrDst == true{
                origin.append(i.Name)
            }else{
                purpose.append(i.Name)
            }
        }
    }
func sendNameToPreviousVC(SelectCity: String) {
print("\(tit) selected ") //return data

        tit = SelectCity
        labelcity!.text = tit

    }
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if segue.identifier == "SelectedCellSegue" {
        if let VC = segue.destinationViewController as? SelectedCity {

            VC.toTake = sendDataToTableview
            VC.delegate = self
        }
    }

}

}

Answer 1

而不是

尝试：

@IBOutlet weak var labelcity: UILabel? = UILabel()

Answer 2

考虑在属性声明中删除弱关键字。使用此关键字可以防止刚创建的UILabel对象被保留，因此该对象会立即释放。

var labelcity: UILabel? = UILabel()

或另一种选择是将对象实例化移动到viewDidLoad方法：

var labelcity: UILabel!
...
override func viewDidLoad() {
    super.viewDidLoad()
    let label = UILabel()
    //you code for subview adding into view controller's view
    labelcity = label
    GetPassCity()
}

Answer 3

我解决了这个问题：

override func viewDidLoad() {
        super.viewDidLoad()
        labelcity.text = tit
        GetPassCity()
    }


func sendNameToPreviousVC(SelectCity: String) {
            tit = SelectCity
        }

UILabel在Swift 2中抛出Thread1：EXC_BAD_ACCESS（代码= 1，地址0x ...）

3 个答案: