Question

让我们说，我有一个处理例外的首选解决方案但有时仍然会出现异常，我不得不使用第二种不太优选的解决方案我使用如下代码，它可能看起来不酷。如果有更好的练习，请咨询。

try:
    print(undefined_varible)
except NameError:
    try:
        print("1st attempt to handle NameError exception")
    except NameError:
        print("2nd attempt to handle NameError exception")

更新：
这是我的真实代码

import re
def find_phone(text):
    try:
        pattern = re.compile(r"(?:\+?(\d{1,3}))?[-. (]*(\d{3})[-. )]*(\d{3})[-. ]*(\d{4})(?: *x(\d+))?")
        #search for a phone number
        mo = pattern.search(text)
        phone = mo.group()
        print (phone)
    except AttributeError:
        try:
            #don't want to use this pattern always because it's too wide and not perfect
            pattern = re.compile(r"(?:\+?(\d{1,3}))?[-. (]*(\d{1,3})[-. )]*(\d{1,3})[-. ]*(\d{1,4})([-. ]*(\d{1,4}))?([-. ]*(\d{1,4}))?(?: *x(\d{1,4}))?")
            mo = pattern.search(text)
            phone = mo.group()
            print (phone)
        except AttributeError:
            print("phone number has not been found")
find_phone("here is the weird formatted phone number: +33 6 29 37 24 57")

Answer 1

我认为这就是你想要的：

import re

def find_phone(text):
    pattern_preference = [
        r"(?:\+?(\d{1,3}))?[-. (]*(\d{3})[-. )]*(\d{3})[-. ]*(\d{4})(?: *x(\d+))?", 
        r"(?:\+?(\d{1,3}))?[-. (]*(\d{1,3})[-. )]*(\d{1,3})[-. ]*(\d{1,4})([-. ]*(\d{1,4}))?([-. ]*(\d{1,4}))?(?: *x(\d{1,4}))?"
    ]
    for pattern in pattern_preference:
        try:
            pattern = re.compile(pattern)
            #search for a phone number
            mo = pattern.search(text)
            phone = mo.group()
            print(phone)
            break
        except AttributeError:
            pass
    else:
        print("phone number has not been found")

find_phone("here is the weird formatted phone number: +33 6 29 37 24 57")

有几种尝试在Python中处理一个异常的好方法是什么？

1 个答案: