Question

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

int main()
{
    ifstream inputFile;
    string example;
    int numbers,
    totalNumbers = 0;

    // Prompt user to input name of the file to open
    cout << "Please enter the name of the program" << endl;
    cin >> example;

    // Open the input file that is assigned to the variable 'example'
    inputFile.open(example.c_str());

    // If the file successfully opened, process it
    if(inputFile)
    {
        // Loop until the EOF is reached
        while(inputFile >> numbers) // If a value was read
        {
            totalNumbers += numbers;
        }

        // Close the file
        inputFile.close(example.c_str());

        cout << totalNumbers;
    }
    else 
    {
        // Display an error message
        cout << "could not access file";
    }

    return 0;
}

错误如下：

fileAdder.cpp：在函数'int main（）'中： fileAdder.cpp:36:40：错误：没有匹配函数来调用'std :: basic_ifstream :: close（const char *）' inputFile.close（example.c_str（））; ^ fileAdder.cpp:36:40：注意：候选人是：在fileAdder.cpp：8：0中包含的文件中： /usr/include/c++/4.8.2/fstream:576:7：注意：void std :: basic_ifstream＆lt; _CharT，_Traits＆gt; :: close（）[with _CharT = char; _Traits = std :: char_traits] 关（） ^ /usr/include/c++/4.8.2/fstream:576:7：注意：候选人需要0个参数，1个提供

Answer 1

ifstream::close确实not接受任何争论。

将第36行更改为inputFile.close();

Answer 2

删除example.c.str（）

正确的陈述是：

inputFile.close();

我们不需要传递参数

C ++编译错误

2 个答案: