Question

我正在尝试制作一个简单的配对应用。该应用程序以所有TextViews以“＃”作为文本开始。当我按下文本字段时，它会变为为该字段存储的字母。

无论如何，我想打开两个字段（我的意思是更改字符串）并进行比较。如果它们相等，则用新字母保持“打开”（例如两者都是“A”）。在字母相同的情况下，一切都很好，但是当字母不同时我会遇到困难。

如果它们不相等，我想让它们用新文本显示一秒钟，然后转到上一个符号（即“＃”）。当我按下第一个字段时，它会更改其文本，但是当我转到第二个字段并且如果它们存储的字母不相等时，第二个字段不会更改文本，并且第一个字段中的文本将返回到上一个字段

如果字符串不相等，我需要做什么才能在短时间内显示带有新文本的字段？

这就是我的表格：

enter image description here

public class MainActivity extends AppCompatActivity {

    TextView textView;
    int counterForPressedFields= 0;
    int textViewForComparationCounter = 0;
    TextView firstTextViewForComparation;
    TextView secondTextViewForComparation;
    int[] nonPressedFields= {1, 1, 1, 1};
    int pressedField = 2;
    int tag = 0;


    public void show(View view) throws InterruptedException {

        textView = (TextView) view;

        tag = Integer.parseInt(textView.getTag().toString());

        if (nonPressedFields[tag] == 1) {

            nonPressedFields[tag] = pressedField;

            if (counterForPressedFields< 2) {
                textViewForComparationCounter += 1;
                counterForPressedFields+= 1;

                switch (tag) {

                    case 0:
                        textView = (TextView) findViewById(R.id.front1);
                        textView.setText("A");
                        break;

                    case 1:
                        textView = (TextView) findViewById(R.id.front2);
                        textView.setText("B");
                        break;

                    case 2:
                        textView = (TextView) findViewById(R.id.front3);
                        textView.setText("A");
                        break;
                    case 3:
                        textView = (TextView) findViewById(R.id.front4);
                        textView.setText("B");
                        break;
                }

                if (textViewForComparationCounter == 1) {
                    firstTextViewForComparation = (TextView) view;
                    firstTextViewForComparation = textView;

                } else if (textViewForComparationCounter == 2) {
                    secondTextViewForComparation= (TextView) view;
                    secondTextViewForComparation= textView;
                }
            }

            if(counterForPressedFields == 2){
                if(firstTextViewForComparation.getText().toString().equals(secondTextViewForComparation.getText().toString())){

                    counterForPressedFields= 0;
                    textViewForComparationCounter = 0;
                }else{

                    firstTextViewForComparation.setText("#");
                    secondTextViewForComparation.setText("#");
                    nonPressedFields[Integer.parseInt(firstTextViewForComparation.getTag().toString())] = 1;
                    nonPressedFields[Integer.parseInt(secondTextViewForComparation.getTag().toString())] = 1;
                    counterForPressedFields= 0;
                    textViewForComparationCounter = 0;
                }
            }

        }

    }


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
    }
}

Answer 1

尝试使用处理程序。您可以将textViews更新回＆＃34;＃＆＃34;使用postDelayed方法。

private final Handler handler = new Handler();
Runnable runnable = new Runnable() {
        public void run() {
            //update your textViews here
        }
    };
handler.postDelayed(runnable, millisecondsOfDelay);

希望它有所帮助！

简单匹配对应用，比较两个TextView

1 个答案: