我正在制作一个基本战舰游戏的剧本。我是python的新手,想要指导哪里出错了。我认为所有代码都在那里需要任何帮助将非常感谢谢谢!
def main():
from random import randint
#initializing board
board = []
for x in range(5):
board.append(["o"] * 5)
def print_board(board):
for row in board:
print( " ".join(row))
#starting the game and printing the board
print ("Let's play Battleship!")
print_board(board)
#defining where the ship is
def random_row(board):
return randint(0, len(board) - 1)
def random_col(board):
return randint(0, len(board[0]) - 1)
ship_row = random_row(board)
ship_col = random_col(board)
#asking the user for a guess
for turn in range(4):
guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))
# if the user's right, the game ends
if guess_row == ship_row and guess_col == ship_col:
print ("Congratulations! You sunk my battleship!")
break
else:
#warning if the guess is out of the board
if (guess_row < 0 or guess_row > 4) or (guess_col < 0 or guess_col > 4):
print ("Oops, that's not even in the ocean.")
#warning if the guess was already made
elif(board[guess_row][guess_col] == "X"):
print ("You guessed that one already.")
#if the guess is wrong, mark the point with an X and start again
else:
print ("You missed my battleship!")
board[guess_row][guess_col] = "X"
# Print turn and board again here
print ( "Turn " + str(turn+1) + " out of 4.")
print_board(board)
#if the user have made 4 tries, it's game over
if turn >= 10:
print ("Game Over")
if __name__ == '__main__':
main()
答案 0 :(得分:1)
首先,您的代码不会像这样运行,因为缩进被破坏了。在Python中,缩进不仅仅是一种好的风格,它使您的程序更具可读性;这是告诉计算机程序结构的原因。修复缩进后,我尝试了你的程序,它按预期工作。但是,不打印“游戏结束”消息,因为在打印时,变量turn
包含最后分配给它的值3
,而不是{{1 }}
对您的代码有一些随意的想法:
10
在定义board
和random_row
的范围内可见,因此您无需将其作为参数传递。电路板尺寸和匝数是硬编码两次;在后一种情况下,你(可能是错误的)使用不同的数字。您可以通过为这些值定义常量(具有无法更改的大写名称的变量)并稍后使用它们来使代码更具可读性:
random_col
在BOARD_WIDTH = 5
BOARD_HEIGHT = 5
MAX_TURNS = 4
...
def random_col():
return random.randint(0, BOARD_WIDTH - 1)
之后,您不需要break
,因为无论如何都会留下循环。
else
括号。