战舰游戏 - if / else的问题

时间:2015-10-15 15:36:16

标签: python python-2.7 if-statement

我遇到了这段代码的问题,当我运行代码时,它总是打印出“糟糕,甚至不在海洋中”。无论我输入什么。此外,如果我写信,代码崩溃。我如何添加一个拼写检查功能,可以解决崩溃,并使代码抵御来自用户的拼写错误。提前谢谢!

from random import randint

#initializing board + this is my list 
board = []

for x in range(5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

#starting the game and printing the board
print "Let's play Battleship!"
print_board(board)

#defining where the ship is
def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)

#asking the user for a guess
for turn in range(4):
    guess_row = raw_input("Guess Row:")
    guess_col = raw_input("Guess Col:")

    # if the user's right, the game ends
    if guess_row == ship_row and guess_col == ship_col:
        print "Congratulations! You sunk my battleship!"
        break
    else:
        #warning if the guess is out of the board
        if (guess_row < 0 or guess_row > 5) or (guess_col < 0 or guess_col > 5):
            print "Oops, that's not even in the ocean."

        #warning if the guess was already made
        elif(board[guess_row][guess_col] == "X"):
            print "You guessed that one already."

        #if the guess is wrong, mark the point with an X and start again           
        else:
            print "You missed my battleship!"
            board[guess_row][guess_col] = "X"

        # Print turn and board again here
        print "Turn " + str(turn+1) + " out of 4." 
        print_board(board)

#if the user have made 4 tries, it's game over
if turn >= 3:
    print "Game Over"

1 个答案:

答案 0 :(得分:2)

你的问题在于raw_input返回一个字符串,你需要把它强制转换成这样的整数:

guess_row = int(raw_input("Guess Row:"))
guess_col = int(raw_input("Guess Col:"))