如何从JSON字符串

时间:2016-04-08 22:34:36

标签: python json

我在txt文件中有以下JSON字符串,我正在尝试从'visualLogs'变量中提取数据帧。我可以读取JSON字符串,我可以访问visualLogs列表,但我整天都没有将它转换为浮点数的9列数据框

{
  "visualScore" : 0,
  "selfReportingResults" : 5,
  "voiceScore" : "No Data",
  "selfReportScore" : 0,
  "subject" : "Baseline for patient: 108",
  "email" : "steven.vannoy@gmail.com",
  "visualLogs" : [
    "time,anger,contempt,disgust,engagement,joy,sadness,surprise,valence\r22.61086,0.00633,0.19347,0.56258,0.18005,0.00223,0.0165,0.31969,0.0\r22.81096,0.00478,0.19439,0.45847,0.09747,0.00188,0.02188,0.22043,0.0\r"
  ],
  "askedQuestions" : [
    "What is your name?",
    "How old are you?",
    "What tim is it?"
  ],
  "voiceCompleteResults" : {
    "status" : "fail"
  }
}

with open(f4lJasonFileName) as data_file:
    feelDat = json.load(data_file)

x = feelDat['visualLogs'][0] # Ultimately there will be more than one of these

我将x转换为数据框的所有尝试都失败了。我已经获得了一个文本值的1列数据框,但这不是我需要的。

我用逗号替换了那些'\ r'字符,最终得到了一列文本数据框,但我希望9列带有标签,然后是浮点行。

1 个答案:

答案 0 :(得分:1)

一旦你加载了json,你需要在\ r \ n然后在逗号上分割:

import  pandas as pd

spl = d["visualLogs"][0].split("\r")


df = pd.DataFrame([v for v in map(lambda x: x.split(","), spl[1:]) if v[0]], columns=spl[0].split(","))

可能更容易理解分成几部分:

import pandas as pd

# split into lines creating an iterator so we don't have to slice.
spl = iter(d["visualLogs"][0].rstrip().split("\r"))

# split first line to get the  column names.
columns = next(spl).split(",")

# split remaining lines into individual rows, removing empty row.
rows = [v for v in (sub_str.split(",") for sub_str in spl) if len(v) > 1]

df = pd.DataFrame(data=rows, columns=columns)

我们也可以spl = iter(d["visualLogs"][0].split()),因为没有其他空格。

或使用 StringIO 对象使用 read_csv

import pandas as pd
spl = d["visualLogs"][0]

from io import StringIO
df = pd.read_csv(StringIO(spl))

这给了你:

      time    anger  contempt  disgust  engagement      joy  sadness  \
0  22.61086  0.00633   0.19347  0.56258     0.18005  0.00223  0.01650   
1  22.81096  0.00478   0.19439  0.45847     0.09747  0.00188  0.02188   

   surprise  valence  
0   0.31969        0  
1   0.22043        0