Question

我目前正在向Microsoft的Emotion API发送请求，请求成功，但收到无效JSON，（无法使用NSJSONSerialization.JSONObjectWithData as! [String: String]或{转换JSON {1}}但可以转换为SwiftyJSON（我可以使用NSArray）。（所有其他选项返回NSArray）

请求

nil

感兴趣的JSON（来自API测试控制台的结果）

    let params = [ "url": "http://reneemullingslewis.com/wp-content/uploads/2014/08/woman-smiling.png" ]
    let body = try? NSJSONSerialization.dataWithJSONObject(params, options: [])
    let url = NSURL(string: "https://api.projectoxford.ai/emotion/v1.0/recognize")!
    let request = NSMutableURLRequest(URL: url)
    request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
    request.setValue("XXXXXXXXXXXXXXXXXXXXXX", forHTTPHeaderField: "Ocp-Apim-Subscription-Key")
    request.HTTPBody = body
    request.HTTPMethod = "POST"

    let task = NSURLSession.sharedSession().dataTaskWithRequest(request){ data, response, error in
        if error != nil{
            print("Error -> \(error)")
            return
        }
        do {
            let result = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? NSArray
            let dResult = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? [String:String]
            let json = JSON(data!)
            print(result)
            print(result?[0]["scores"]??["anger"]) //Is works
            print(dResult) //Returns nil
            print(json) //Returns 'unknown'

        } catch {
            print(error)
        }
    }

    task.resume()

NSArray结果

[
  {
    "faceRectangle": {
      "height": 208,
      "left": 172,
      "top": 128,
      "width": 208
    },
    "scores": {
      "anger": 2.46091458E-05,
      "contempt": 0.297730684,
      "disgust": 9.475541E-05,
      "fear": 1.13360545E-06,
      "happiness": 0.564267159,
      "neutral": 0.131727561,
      "sadness": 1.14351078E-05,
      "surprise": 0.0061426633
    }
  }
]

Answer 1

[String:String]（又名Dictionary<String,String>）是一个字典，而不是一个数组，JSON的常见Swift数组类型是[[String:AnyObject]]（又名Array<Dictionary<String,AnyObject>>）

返回的JSON无效：无法解析为[String：String]但作为NSArray工作

1 个答案: