Question

这是我对服务器的JSON响应： -

{
    "Details": [
        {
            "ID": 234872,
            "Name": "asdfg",
            "Address": "hasgdkjfgsjaf,asfuysdfg",
            "Email": "",
            "Mobile": "",
            "Profile": "gwekjrg ",
            "Amt": 0,
            "Date": ""
        }
    ]
}

这是我编写的js代码，用于解析它并在我的应用程序中使用它： -

function getDetail(madeUrl) {
        $.ajax({
        url: madeUrl,
        type : "GET",
        dataType : "json",
        contentType: "application/json",
        success: function(msg) {
                $("#detail tr").remove();
                var searchResponse = msg.Details;
                var html;
                $.each(searchResponse, function(index, data) {
                    html = '<tr><td>' + data.Name + '</td> <td>' + data.Amt + '</td></tr>' + data.Profile + '</td></tr>' + data.Date + '</td></tr>';
                    $("#detail").append(html);
                });
                $('#report').fadeIn();
            },
            error: function (xhr, ajaxOptions, thrownError) {
                alert("errorstatus: " + xhr.status + " ajaxoptions: " + ajaxOptions + " throwError: " + thrownError);
            },
            complete : function() {

            }
        });
}

但它会抛出一个错误，就像无法解析JSON字符串。无法找出原因。有什么帮助吗？

Answer 1

请尝试此代码。它对我来说很好。希望它对你有所帮助。请告诉我。感谢。

<强> HTML

<div id="detail"></div>

<强>脚本：

var j ='{"Details": [{"ID": "234872","Name": "asdfg","Address": "hasgdkjfgsjaf,asfuysdfg","Email": "","Mobile": "","Profile": "gwekjrg ","Date": ""}]}';

var json = $.parseJSON(j).Details;
$(json).each(function(i,val){
    $.each(val,function(k,v){
    console.log(k+" : "+ v); 
    $("#detail").append(k+" : "+ v + " <br />");
});
});

演示网址：

Demo

Answer 2

如果您有不可解析的JSON消息，则意味着JQuery不会将您的JSON视为有效。

可以肯定的是，我会从ajax调用中删除dataType和contentType（默认数据类型为“Intelligent Guess”，这意味着jquery会在检测到它时自动解析JSon，否则发送文本）并在开头添加以下行成功的功能：

alert(msg === Object(msg)?"json received:\n"+JSON.stringify(msg):"text received:\n"+msg);

无法解析JSON字符串

2 个答案: