Question

我想构建一个与逗号（,）分隔的IP字符串匹配的RegEx，或者字符串只有*。字符串不应该同时具有IP地址和*

验证IP，即1.1.1.1（数字和.点字符）。此外，仅允许*
*存在，不存在其他IP。

这是正则表达式

(((25[0-5]|2[0-4]\d|[01]?\d\d?)\.(25[0-5]|2[0-4]\d|[01]?\d\d?)\.(25[0-5]|2[0-4]\d|[01]?\d\d?)\.(25[0-5]|2[0-4]\d|[01]?\d\d?)(,\n|,?))|(,*))

测试字符串：

192.168.1.1,192.56.3.23,189.35.2.2,198.23.45.56,198.168.1.255

如何查看*？

Answer 1

您可以使用

^(?:(?:25[0-5]|2[0-4]\d|[01]?\d\d?)\.(?:25[0-5]|2[0-4]\d|[01]?\d\d?)\.(?:25[0-5]|2[0-4]\d|[01]?\d\d?)\.(?:25[0-5]|2[0-4]\d|[01]?\d\d?)|\*)(?:,\s*(?:(?:25[0-5]|2[0-4]\d|[01]?\d\d?)\.(?:25[0-5]|2[0-4]\d|[01]?\d\d?)\.(?:25[0-5]|2[0-4]\d|[01]?\d\d?)\.(?:25[0-5]|2[0-4]\d|[01]?\d\d?)|\*))*$

请参见regex demo

Expanded//verbose/free-spacing version：

^         # start of string
 (?:      # start of a grouping
  (?:     # start of another grouping
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)\. # First octet and .
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)\. # Second octet and .
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)\. # Third octet and .
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)   # Fourth octet
   |\*                               # or just a * char instead of an IP
  )                                  # end of another grouping
 )                                   # end of grouping
 (?:,\s*             # a group that will repeat 0+ times, matches , then 0+ whitespaces   
  (?:                # an IP matching grouping
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)\. # First octet and .
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)\. # Second octet and .
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)\. # Third octet and .
   (?:25[0-5]|2[0-4]\d|[01]?\d\d?)   # Fourth octet
  |\*)                               # Or a *
 )*                                  # ... zero or more times 
$                                    # end of string

用逗号或*分隔的IP地址的正则表达式

1 个答案: