用双立方法进行C ++图像插值

时间:2016-04-07 07:24:08

标签: c++ image-processing bicubic

我只是想通过BiCubic插值来平滑图像。我得到了一些用于插入RGB图像的代码。我已将代码更改为适用于灰度图像。但结果我只得到了完全黑色的图像。考虑输入和输出图像大小相同。代码粘贴在下面。请帮我。提前谢谢。

 inline Uint16 saturate(float x, unsigned max_pixel)
{
    return x > max_pixel ? max_pixel
        : x < 0.0f ? 0
        : Uint16(x);
}

inline float get_subpixel(const Uint16* in, std::size_t dest_width, std::size_t dest_height, unsigned x, unsigned y)
{
    if (x < dest_width && y < dest_height)
        return in[(y * dest_width) + x];

    return 0;
}


void interpolate(unsigned dest_width, unsigned dest_height, unsigned bits_allocated, const Uint16* src, Uint16** dest)
{
    const double tx = 1;
    const double ty = 1;
    float C[5] = { 0 };
    unsigned max_bit = pow(2, bits_allocated);

    for (unsigned i = 0; i < dest_height; ++i)
    {
        for (unsigned j = 0; j < dest_width; ++j)
        {
            const float x = float(tx * j);
            const float y = float(ty * i);
            const float dx = tx * j - x, dx2 = dx * dx, dx3 = dx2 * dx;
            const float dy = ty * i - y, dy2 = dy * dy, dy3 = dy2 * dy;


            for (int jj = 0; jj < 4; ++jj)
            {
                const int idx = y - 1 + jj;
                float a0 = get_subpixel(src, dest_width, dest_height, x, idx);
                float d0 = get_subpixel(src, dest_width, dest_height, x - 1, idx) - a0;
                float d2 = get_subpixel(src, dest_width, dest_height, x + 1, idx) - a0;
                float d3 = get_subpixel(src, dest_width, dest_height, x + 2, idx) - a0;
                float a1 = -(1.0f / 3.0f) * d0 + d2 - (1.0f / 6.0f) * d3;
                float a2 = 0.5f  * d0 + 0.5f *  d2;
                float a3 = -(1.0f / 6.0f) * d0 - 0.5f * d2 + (1.0f / 6.0f) * d3;
                C[jj] = a0 + a1 * dx + a2 * dx2 + a3 * dx3;

                d0 = C[0] - C[1];
                d2 = C[2] - C[1];
                d3 = C[3] - C[1];
                a0 = C[1];
                a1 = -(1.0f / 3.0f) * d0 + d2 - (1.0f / 6.0f) * d3;
                a2 = 0.5f  * d0 + 0.5f  * d2;
                a3 = -(1.0f / 6.0f) * d0 - 0.5f * d2 + (1.0f / 6.0f) * d3;
                (*dest)[i * dest_width + j] = saturate(a0 + a1 * dy + a2 * dy2 + a3 * dy3, max_bit);
            }
        }
    }
}

2 个答案:

答案 0 :(得分:1)

你怎么能有这个? c没有计算,直到jj循环结束,括号应该在d之上 - 我不考虑该方法是否正确。

UIImage *myImage = [UIImage imageNamed:@"myImageFile.png"];
myImage = [myImage imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];

imageView.image = myImage;
imageView.tintColor = [UIColor greenColor] // or any other color you want

答案 1 :(得分:0)

我想分享很棒的链接 cubic splines