Google的Buckyball涂鸦是如何实现的？
我已经看过它创建的标记，即原子的一堆
图像，以及big background image，它用来创建债券的过程非常奇怪。
有些事我无法解决：
- javascript在哪里
- 是什么让后面的债券变得更窄
- 为什么原子也应用了粘合背景
对于那些感兴趣的人来说，这是谷歌涂鸦的样子：
2 个答案:
答案 0 :(得分：14)
如果你看一下标记，它只是一堆带有位置属性的图像和div，将它们组成一种网格。这个文件：http://www.google.com/logos/2010/buckyball10-hp-bond.png是一个包含每个方向的每个键的精灵。这个图像是原子：http://www.google.com/logos/2010/buckyball10-hp-atom.png。他们使用的JavaScript通过改变它们的位置来动画这些元素。
JavaScript位于Google徽标和涂鸦标记之后的Script元素中。后部粘合看起来更窄，因为它们的不透明度变得稍微透明。最后，它看起来不像原子具有键背景。他们有自己的精灵（如上所述。）
答案 1 :(得分：10)
好的，这是javascript，在运行jsBeautifier之后：
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[-l, -k, -e - n],
[-n, -e, -k - l],
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[-k - l, -n, -e],
[-k, -e - n, l],
[-e, -k - l, n],
[e, -k - l, n],
[k, -e - n, l],
[-l, -k, e + n],
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this.a.style.height = this.d + "px"
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this.a = document.createElement("div");
this.a.className = "logo-dust"
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this.a.style.top = f + "px";
this.a.style.left = b + "px";
this.opacity = 1;
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r.appendChild(this.a);
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this.opacity -= 0.02;
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Z.prototype.h = function () {
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google.dom.remove(this.a);
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t && I && Math.sqrt(J * J + K * K) < 30 && X()
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eval("function modulo(a,n){return a" + "%%".charAt(0) + "n;}");
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b.src = z.src;
b.border = 0;
b.style.position = "absolute";
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b.style.filter = "";
if (g) b.style.backgroundImage = "url(" + s.src + ")"
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},
ga = function (b, f) {
var g = f > 1 ? 1 : Math.pow(f, 4);
ia(b, g, a)
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google.doodle.init = function () {
if (window.location.href.indexOf("#") == -1) if (r = document.getElementById("hplogo")) if (!fa) {
fa = a;
google.j && google.j.en && $(100, pa, function () {
return google.rein && google.dstr
});
$(100, qa, function () {
return google.listen && google.browser && google.dom
})
}
};
var $ = function (b, f, g) {
if (g()) f();
else b < 200 && window.setTimeout(function () {
$(b + 1, f, g)
}, b)
},
pa = function () {
if (!google.doodle.k) {
google.doodle.k = a;
google.rein.push(google.doodle.init);
google.dstr.push(ra)
}
},
qa = function () {
W = google.browser.engine.IE;
sa();
google.listen(document, "mousemove", ja);
for (var b = 0; o[b++];) D.push(oa());
for (b = 0; q[b++];) E.push(new Y);
for (; F.length < 40;) F.push(new Z);
B = oa();
B.width = B.height = 7;
V = window.setInterval(ha, 30);
ea = window.setTimeout(ta, 5E3)
},
ta = function () {
if (t) X();
else v = a
},
sa = function () {
z = new Image;
z.onload = function () {
A = a
};
z.src = "/logos/2010/buckyball10-hp-atom.png";
if (W) {
u = new Image;
u.onload = function () {};
u.src = "/logos/2010/buckyball10-hp-bond-ie.png"
}
s = new Image;
s.onload = function () {
t = a;
v && X()
};
s.src = "/logos/2010/buckyball10-hp-bond.png"
},
ra = function () {
google.unlisten(document, "mousemove", ja);
window.clearInterval(V);
window.clearTimeout(ea)
}
} catch (ua) {
google.ml(ua, c, {
_sn: "BKY"
})
};
})();
google.doodle.init()
不是很漂亮吗？
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