C++ error: invalid conversion from 'int' to 'const char*' [-fpermissive]|

Question

First of all, i need to say, that i am a complete noob. I am trying to make some naval combat simulation to do that i created a random letter and number generator Here's the code. By the way, what i want to achieve is to have only one variable (Guess) to be confronted with the ship places that the user specified.

char letters[]= {'A','B','C','D','E','F','G','H','I','L'};

\\ lots of code

//RandomAI
int G = rand() % 10 + 1;
int nOut = rand() % 10 + 1;
char lOut = letters[G];
string Guess = lOut + nOut;
return 0;

Answer 1

string Guess = lOut + nOut; adds an int and char types which does not produce a std::string. One way to address this is to create a string and then append to it:

std::string guess =  lOut + std::to_string(nOut);

This will solve your compiler error, but you still have a logic error here:

int G = rand() % 10 + 1;

rand() % 10 + 1 will produce a value between 1 and 10 inclusive. You want a number between 0 and 9 inclusive, because indices in C++ begin at 0, not 1. So drop the +1 portion:

int G = rand() % 10;

Otherwise you may accidentally attempt to access an out-of-bounds index in letters

Answer 2

假设您想要一个类似'A7'或'F2'的输出字符串，实现此目的的一种方法是将所有内容转换为string（因为您无法添加int和{{ {1}}）。对于那些无法访问C ++ 11和char的人，您可以使用：

std::to_string()