Question

我遇到了错误，我无法弄清楚原因。

我有一个子类:(标题）

    class motionSensor: public sensorLeaf
{
public:
    motionSensor(const int& sensorID, const int& sensorType, bool sensorActivate);

继承自超类＆＃34; sensorLeaf＆＃34;

子类有2个私有变量

const float minDistance; const float maxDistance;

在我的班级文件中;这是我的构造函数：

    motionSensor::motionSensor(const int &sensorID, const int &sensorType, bool sensorActivate)
 :sensorLeaf(sensorID, sensorType, sensorActivate), minDistance{1.0f}, maxDistance{5.0f}

但是一旦我编译它，我就会得到以下错误：

/home/jb/EmergencySensor/motionsensor.cpp:8: error: invalid conversion from 'int' to 'const char*' [-fpermissive]
  :sensorLeaf(sensorID, sensorType, sensorActivate), minDistance{1.0f}, maxDistance{5.0f}
                                                                                        ^

Sensorleaf构造函数是：

sensorLeaf::sensorLeaf(const int sensorID, const std::string sensorType, bool sensorActivate)
{
    _sensorID = sensorID;
    _sensorType = sensorType;
    _sensorActivate = sensorActivate
}

使用私有变量：

private:  
    int _sensorID;
    std::string _sensorType;
    bool _sensorActivate;

};

在做了一些研究之后，我发现当你将一个字符串定义为＆＃39; ＆＃39;而不是＆＃34; ＆＃34;但是我没有在任何地方使用它。

Answer 1

您正试图从const int &sensorType构造函数强制motionSensor到const std::string sensorType sensorLeaf构造函数。{/ p>

 motionSensor::motionSensor(const int &sensorID, const int &sensorType, bool sensorActivate)
------------------------------------------------------------^
 :sensorLeaf(sensorID, sensorType, sensorActivate), minDistance{1.0f}, maxDistance{5.0f}
-----------------------^

sensorLeaf::sensorLeaf(const int sensorID, const std::string sensorType, bool sensorActivate)
-------------------------------------------------------------^

错误：来自＆＃39; int＆＃39;的转换无效到＃char; char *＆＃39; [-fpermissive]

1 个答案: