Question

我有一个架构，我想在列表上有一个特定的约束。在Employees下的Firm元素中，我需要员工列表中的所有DepartmentId元素都相同。因此，如果Firm的实例具有DepartmentId 1378，则Firm对象仅在所有Employees具有相同ID时才有效。这可能与XSD有关吗？最好将其放在此处，因此在代码中针对XSD验证对象后，我不需要检查这一点。

<element name="Firm">
    <complexType>
        <sequence>
            <element name="Name" type="string" />
            <element name="Employees" type="tns:Employee" minOccurs="1" maxOccurs="unbounded" />
        </sequence>
    </complexType>
</element>

<complexType name="Employee">
    <sequence>
        <element name="EmployeeId" type="string" />
        <element name="DepartmentId" type="string" />
        <element name="Department" type="string" />
        <element name="Name" type="string" />
        <element name="Description" type="string" />
    </sequence>
</complexType>

Answer 1

XSD 1.0

你的约束不能在XSD 1.0中表达。

XSD 1.1

您的约束可以通过xs:assert在XSD 1.1中表达：

<xs:assert test="count(distinct-values(tns:Employees/tns:DepartmentId)) = 1"/>

在上下文中......

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns:tns="http://example.com/tns"
    targetNamespace="http://example.com/tns"
    xmlns:vc="http://www.w3.org/2007/XMLSchema-versioning"
    elementFormDefault="qualified"
    vc:minVersion="1.1">
    <xs:element name="Firm">
        <xs:complexType>
            <xs:sequence>
                <xs:element name="Name" type="xs:string" />
                <xs:element name="Employees" type="tns:Employee"
                            minOccurs="1" maxOccurs="unbounded" />
            </xs:sequence>
            <xs:assert test="count(distinct-values(tns:Employees/tns:DepartmentId))
                             = 1"/>
        </xs:complexType>
    </xs:element>

    <xs:complexType name="Employee">
        <xs:sequence>
            <xs:element name="EmployeeId" type="xs:string" />
            <xs:element name="DepartmentId" type="xs:string" />
            <xs:element name="Department" type="xs:string" />
            <xs:element name="Name" type="xs:string" />
            <xs:element name="Description" type="xs:string" />
        </xs:sequence>
    </xs:complexType>
</xs:schema>

然后此XML将有效：

<?xml version="1.0" encoding="UTF-8"?>
<Firm>
    <Name></Name>
    <Employees>
        <EmployeeId></EmployeeId>
        <DepartmentId>1378</DepartmentId>
        <Department></Department>
        <Name></Name>
        <Description></Description>
    </Employees>
    <Employees>
        <EmployeeId></EmployeeId>
        <DepartmentId>1378</DepartmentId>
        <Department></Department>
        <Name></Name>
        <Description></Description>
    </Employees>
</Firm>

但此XML将无效：

<?xml version="1.0" encoding="UTF-8"?>
<Firm>
    <Name></Name>
    <Employees>
        <EmployeeId></EmployeeId>
        <DepartmentId>1378</DepartmentId>
        <Department></Department>
        <Name></Name>
        <Description></Description>
    </Employees>
    <Employees>
        <EmployeeId></EmployeeId>
        <DepartmentId>9999</DepartmentId>
        <Department></Department>
        <Name></Name>
        <Description></Description>
    </Employees>
</Firm>

根据要求

。

XML Schema - 列表中变量的约束

1 个答案:

XSD 1.0

XSD 1.1