Question

我有两个pandas数据帧。第一个是：

df1 = pd.DataFrame({"val1" : ["B2","A1","B2","A1","B2","A1"]})

第二个数据框是：

df2 = pd.DataFrame({"val1" : ["A1","A1","A1","B2","B2","B2"],
                    "val2" : [10, 13, 16, 11, 20, 22]})

我想将两者合并在一起，使用df1的行排序，df2的值遵循此顺序。理想情况下，我希望它看起来像这样：

df_final = pd.DataFrame({"val1" : ["B2","A1","B2","A1","B2","A1"],
                         "val2" : [11, 10, 20, 13, 22, 16]})

我尝试过使用left_on和right_on的merge函数，但是我没有得到我正在寻找的输出。任何帮助将不胜感激。

Answer 1

你可以这样做：

按df2对['val1', 'val2']中的值进行排序，按val1对其进行分组并将其存储为g2？
将idx列添加到df1，以便从df2

代码：

In [176]: df1['idx'] = 1

In [177]: df1['idx'] = df1.groupby('val1')['idx'].cumsum()-1

In [178]: df1
Out[178]:
  val1  idx
0   B2    0
1   A1    0
2   B2    1
3   A1    1
4   B2    2
5   A1    2

In [179]: g2 = df2.sort_values(['val1', 'val2']).groupby('val1')

In [180]: g2.groups
Out[180]: {'A1': [0, 1, 2], 'B2': [3, 4, 5]}

In [181]: df2.iloc[g2.groups['A1'][1]]
Out[181]:
val1    A1
val2    13
Name: 1, dtype: object

In [182]: df1.apply(lambda x: df2.iloc[g2.groups[x['val1']][x['idx']]], axis=1)
Out[182]:
  val1  val2
0   B2    11
1   A1    10
2   B2    20
3   A1    13
4   B2    22
5   A1    16

Answer 2

您可以使用groupby/cumcount为每个组中的每一行分配一个唯一编号：

df1['cumcount'] = df1.groupby('val1').cumcount()
#   val1  cumcount
# 0   B2         0
# 1   A1         0
# 2   B2         1
# 3   A1         1
# 4   B2         2
# 5   A1         2

如果我们对df2执行相同操作：

df2['cumcount'] = df2.groupby('val1').cumcount()
#   val1  val2  cumcount
# 0   A1    10         0
# 1   A1    13         1
# 2   A1    16         2
# 3   B2    11         0
# 4   B2    20         1
# 5   B2    22         2

然后将df1与df2合并在公共列（val1和cumcount）上会产生所需的结果：

import numpy as np
import pandas as pd

df1 = pd.DataFrame({"val1" : ["B2","A1","B2","A1","B2","A1"]})
df2 = pd.DataFrame({"val1" : ["A1","A1","A1","B2","B2","B2"],
                    "val2" : [10, 13, 16, 11, 20, 22]})
df_final = pd.DataFrame({"val1" : ["B2","A1","B2","A1","B2","A1"],
                         "val2" : [11, 10, 20, 13, 22, 16]})

df1['cumcount'] = df1.groupby('val1').cumcount()
df2['cumcount'] = df2.groupby('val1').cumcount()
result = pd.merge(df1, df2, how='left')
result = result.drop('cumcount', axis=1)
print(result)
assert result.equals(df_final)

产量

  val1  val2
0   B2    11
1   A1    10
2   B2    20
3   A1    13
4   B2    22
5   A1    16

请注意，与how='left'合并会产生与第一个DataFrame df1相同行数的结果，并保持与df1相同的行顺序。

Python Pandas-根据索引顺序合并两个数据帧

2 个答案: