又回来了另一个问题。我正在努力打造一个桌面制造商" - 现在只需创建带字典和检查键的文件。
我有两个问题:首先我不知道是否存在用于写入二进制文件的文件格式,但是如果它已经存在则不会覆盖以前的文件?我尝试了(try,except)方法但是例外的FileExistsError永远不会出现:/(在createTable函数中)
其次我在创建列表时遇到问题。我创建了一个循环,要求将条目和值存储在单独的列表中。这些列表稍后将被压缩成字典并腌制成文件。 (在createTable函数中)
当然,如果还有其他错误我爱他们指出:)
import pickle
def checkTable(nameOfTable) :
try :
#seeing what is it they are looking for
prompt = input("What do you want to check?\n")
with open("%s.pkl" % nameOfTable, "rb") as f:
data = pickle.load(f)
#getting what they want from the data from table
whatTheyWant = data.get(prompt, "There is nothing like that in the table.\n")
print(whatTheyWant)
#if table doesn't exist
except IOError as e:
print("Sorry such a directory doesn't exist.\n")
def createTable(nameOfYourTable) :
try :
#opens a new file with the table
with open("%s.pkl" %nameOfYourTable, "wb+") as f :
decision = "yes"
if decision == "yes" :
#asking for entries and keys to put into the table
#creates lists with entries and values to be zipped together
entry.append = input("What is the entry?\n")
value.append = input("What is the value of the entry?\n")
decision = input("Do you want to go on? (yes/no)\n")
i += 1
else :
#getting it all into a dictionary and putting it into a file
table={dict(zip(entry, value))}
pickle.dump(table, f)
#if a file with the name already exists
except FileExistsError as e :
print("Sorry, a file with this name already exists.")
#what the person wants to do
answer = input("Hello. Do you want to create a table or check an existing one?\n")
#asking for the name of the new table
if answer == "create" :
nameOfYourTable = input("What do you want the table to be called?\n")
createTable(nameOfYourTable)
#asking what table to look in
elif answer == "check" :
nameOfTable = input("What is the name of the table?\n")
checkTable(nameOfTable)
else :
print("\nThat's not a valid option.\n")
print("Thank you for using me. It was very nice.")
答案 0 :(得分:1)
根据您的需要,您可以根据需要设置文件模式,open(file, "x")
,添加b
或t
。
在x
模式下,只有 时才会创建文件,否则会引发异常。 createTable
函数对我来说没有意义。 decision = "yes"
然后if decision == "yes":
? decision
应该是global
?这很模糊。
答案 1 :(得分:0)
你需要先从文件中读取列表,添加到列表中,然后在最后写一个新的pickle文件。顺便说一句,您可以检查文件是否存在os.path.exists
。使用list_name.append(new_item)
将项目添加到列表中。您需要先使用list_name = []
初始化列表。