字符串中的MySQL SUM编号

Question

我有movies表

SELECT * FROM movies

+-----------------------------------+---------------------------------------------------------+
|            MovieTitle             |                         Awards                          |
+-----------------------------------+---------------------------------------------------------+
| Rocky 20                          | Nominated for 1 Oscar. Another 37 wins & 46 nominations |
| Die Hard 51                       | Won 1 Oscar. Another 5 wins & 19 nominations.           |
| Killer tomatoes                   | 9 nominations.                                          |
+-----------------------------------+---------------------------------------------------------+

我希望能SUM Awards +-----------------------------------+---------------------------------------------------------+-------+ | MovieTitle | Awards | Total | +-----------------------------------+---------------------------------------------------------+-------+ | Rocky 20 | Nominated for 1 Oscar. Another 37 wins & 46 nominations | 84 | | Die Hard 51 | Won 1 Oscar. Another 5 wins & 19 nominations. | 25 | | Killer tomatoes | 9 nominations. | 9 | +-----------------------------------+---------------------------------------------------------+-------+ 中所有奖项/提名的数量，以便有类似的内容：

{{1}}

关于如何只使用MySQL实现这一目标的任何建议？

Answer 1

你的字符串都在寻找“提名”，“胜利”和“奥斯卡”之前的数字。这简化了问题。

您可以使用字符串操作获取所需的值。这是一个解决方案：

select ((case when awards like '% nominations%'
              then substring_index(substring_index(awards, ' nominations', 1), ' ', -1) + 0
              else 0
         end) +
        (case when awards like '% wins%'
              then substring_index(substring_index(awards, ' wins', 1), ' ', -1) + 0
              else 0
         end) +
        (case when awards like '% Oscar%'
              then substring_index(substring_index(awards, ' Oscar', 1), ' ', -1) + 0
              else 0
         end)
        ) as TotalMentions

我可以理解必须处理关系数据库中格式不正确的数据。在这种情况下，字符串形成得很好，所以解决方案并非那么不合理。

Answer 2

SELECT SUM(column_name) FROM table_name;

或

SELECT SUM(Quantity) AS TotalItemsOrdered FROM OrderDetails;

我希望这有帮助！