Question

我正在准备一个代码，它将字符串拆分为字符数组，然后根据某种模式对每个数组进行混洗。

我已经使用了一些代码根据“keysize”将数组拆分到不同的char数组，并且它工作正常，除了可能缺少某些元素的最后一个数组。

如果最后一个数组比其他数组短，则会抛出异常，因为在某些时候交换功能可能试图将[0]与不存在的[x]交换。

那么如何将最后一个数组填充为相同的大小？

这是我在这里的一个问题中找到的分裂代码，我在其中编辑了使用 char 而不是 int 。

public static char[][] Split(char[] source, int keysize)
    {
        int fullArrayCount = source.Length / keysize;
        int totalArrayCount = fullArrayCount;
        int remainder = source.Length - (fullArrayCount * keysize);
        if (remainder > 0)
        {
            totalArrayCount++;
        }
        char[][] output = new char[totalArrayCount][];
        for (int i = 0; i < fullArrayCount; i++)
        {
            output[i] = new char[keysize];
            Array.Copy(source, i * keysize, output[i], 0, keysize); // Array.Copy(Original Array,,Target array,"Where to start"0,Howmuch)
        }
        if (totalArrayCount != fullArrayCount)
        {

            output[fullArrayCount] = new char[remainder];
           // output[fullArrayCount] = new char[keysize];
            MessageBox.Show((keysize-remainder).ToString());
            Array.Copy(source, fullArrayCount * keysize,output[fullArrayCount], 0, remainder);

        }
        return output;
    }

Answer 1

不能只是代替：

$(".widget_body").on("mousedown", "canvas", function() {

    var id = $(this).attr("id");
    var canvas = document.getElementById(id);
    var canvas,
        context,
        dragging = false,
        dragStartLocation,
        snapshot;

    fitToContainer(canvas);

    function fitToContainer(canvas){
      // Make it visually fill the positioned parent
      canvas.style.width ='100%';
      canvas.style.height='100%';
      // ...then set the internal size to match
      canvas.width  = canvas.offsetWidth;
      canvas.height = canvas.offsetHeight;
    }


    function getCanvasCoordinates(event) {
        var x = event.clientX - canvas.getBoundingClientRect().left,
            y = event.clientY - canvas.getBoundingClientRect().top;

        return {x: x, y: y};
    }

    function takeSnapshot() {
        snapshot = context.getImageData(0, 0, canvas.width, canvas.height);
    }

    function restoreSnapshot() {
        context.putImageData(snapshot, 0, 0);
    }


    function drawLine(position) {
        context.beginPath();
        context.moveTo(dragStartLocation.x, dragStartLocation.y);
        context.lineTo(position.x, position.y);
        context.stroke();
    }

    function dragStart(event) {
        dragging = true;
        dragStartLocation = getCanvasCoordinates(event);
        takeSnapshot();
    }

    function drag(event) {
        var position;
        if (dragging === true) {
            restoreSnapshot();
            position = getCanvasCoordinates(event);
            drawLine(position);
        }
    }

    function dragStop(event) {
        dragging = false;
        restoreSnapshot();
        var position = getCanvasCoordinates(event);
        drawLine(position);
    }

    function clearCanvas(event) {
        context.clearRect(0, 0, canvas.width, canvas.height);
    }


    context = canvas.getContext('2d');
    context.strokeStyle = 'purple';
    context.lineWidth = 4;
    context.lineCap = 'round';

    canvas.addEventListener('mousedown', dragStart, false);
    canvas.addEventListener('mousemove', drag, false);
    canvas.addEventListener('mouseup', dragStop, false);
    canvas.addEventListener('dblclick', clearCanvas, false);
    });

写：

output[fullArrayCount] = new char[remainder];

Answer 2

将一组字符拆分为指定长度的字符数组的集合，用管道符号填充，可以轻松替换/删除/搜索。（它不喜欢空炭）

public static List<char[]> Split(char[] source, int keysize)
{
    List<char[]> list = new List<char[]>();

    for (int i = 0; i < source.Length; i+= keysize)
    {
        List<char> c = source.Skip(i).Take(keysize).ToList();
        while (c.Count < keysize)
        {
            c.Add('|');
        }
        list.Add(c.ToArray());
    }
    return list;
}

static void Main(string[] args)
{

    var x = Split("abcdefgh".ToCharArray(), 3);

    Console.ReadLine();
}

如何在C＃中填充数组？

2 个答案: