Question

是否可以使用递增的数字填充数组？例如

$myArr = ["red", "green", "blue"];
$type = "colour";

我想以某种方式合并这些并添加排序顺序，所以我最终得到以下

Array
(
    [red] => Array
        (
            [type] => "colour"
            [sort] => 1
        )
    [green] => Array
        (
            [type] => "colour"
            [sort] => 2
        )
    [blue] => Array
        (
            [type] => "colour"
            [sort] => 3
        )
)

到目前为止，我只管理过：

$additional_data = array_pad([], count($myArr), ['type_id' => $type_id]);
$data = array_combine($myArr, $additional_data);

正在屈服：

Array
(
    [red] => Array
        (
            [type] => "colour"
        )
    [green] => Array
        (
            [type] => "colour"
        )
    [blue] => Array
        (
            [type] => "colour"
        )
)

我知道我可以通过迭代颜色来做到这一点，但想知道是否可以在没有循环的情况下完成。

由于

Answer 1

我这样做了，希望可以帮忙

$myArr = ["red", "green", "blue"];
$type = "colour";

$x = array();
for($i=0;$i<count($myArr);$i++){
$x[$myArr[$i]]=array();
$x[$myArr[$i]]["type"]=$type;
$x[$myArr[$i]]["sort"]=$i;
}
var_dump($x);

Answer 2

您为解决此问题而发布的版本始终将1作为sort_order。

const cursor = db.collection('name').aggregate(
    [
        {
            "$match": {code: 10}
        },
        {
          "$count": "count"
        }
    ],
    {
        "allowDiskUse": false
    }
)

for (let doc = await cursor.next(); doc != null; doc = await cursor.next()) {
    console.log('aggregate:', doc.count);
}

...输出

$myArr = ["red", "green", "blue"];
$type_id = "colour";
$sort = 0;

$additional_data = array_pad([], count($myArr), ['type_id' => $type_id, 'sort_order' => ++$sort]);
$data = array_combine($myArr, $additional_data);
print_r($data);

然后，您可以使用array_walk处理结果以更正值...

Array
(
    [red] => Array
        (
            [type_id] => colour
            [sort_order] => 1
        )

    [green] => Array
        (
            [type_id] => colour
            [sort_order] => 1
        )

    [blue] => Array
        (
            [type_id] => colour
            [sort_order] => 1
        )

)

它纠正了它。

$myArr = ["red", "green", "blue"];
$type_id = "colour";
$sort = 0;

$additional_data = array_pad([], count($myArr), ['type_id' => $type_id, 'sort_order' => ++$sort]);
$data = array_combine($myArr, $additional_data);
$sort = 1;
array_walk($data, function (&$item, $key) use(&$sort) {
    $item['sort_order'] = $sort++;
});

print_r($data);

Answer 3

我明白了。非常简单。

$myArr = ["red", "green", "blue"];
$type = "colour";
$sort = 0;

$additional_data = array_pad([], count($myArr), ['type_id' => $type_id, 'sort_order' => ++$sort]);
$data = array_combine($myArr, $additional_data);

填充数字递增的数组

3 个答案: