Question

我正在使用以下代码进行电子邮件验证。如果电子邮件ID以数字开头，那么它不接受，我想接受 123a@asd.com 。请建议我。

BOOL stricterFilter = NO; 
NSString *stricterFilterString = @"^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2,4}$";
NSString *laxString = @"^.+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2}[A-Za-z]*$";
NSString *emailRegex = stricterFilter ? stricterFilterString : laxString;
NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", emailRegex];
return [emailTest evaluateWithObject:emailID];

提前致谢

Answer 1

NSString *mailreg=@"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";
NSPredicate *mailtest=[NSPredicate predicateWithFormat:@"SELF MATCHES %@",mailreg];
[mailtest evaluateWithObject:checkString]

试试这个

Answer 2

这是我的观察，检查可能是你正在添加空白，这就是为什么它没有正确验证它 - 正如@Petesh在评论中也提到 - 很好的解释人。

-(BOOL)validate:(NSString *)emailID {
    BOOL stricterFilter = YES;
    NSString *stricterFilterString = @"^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2,4}$";
    NSString *laxString = @"^.+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2}[A-Za-z]*$";
    NSString *emailRegex = stricterFilter ? stricterFilterString : laxString;
    NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", emailRegex];
    return [emailTest evaluateWithObject:emailID];
}

-(void)validateEmails   {
    if ([self validate:@" 123a@asd.com"]   == true)    {
        NSLog(@"true");
    } else {
        NSLog(@"false"); //Result
    }

    if ([self validate:@"123a@asd.com"]   == true)    {
        NSLog(@"true"); //Result
    } else {
        NSLog(@"false");
    }

    if ([self validate:@"myemail@gmail.com"]   == true)    {
        NSLog(@"true"); //Result
    } else {
        NSLog(@"false");
    }

    if ([self validate:@"my?email@gmail.com"]   == true)    {
        NSLog(@"true");
    } else {
        NSLog(@"false"); //Result
    }
}

不接受以号码开头的电子邮件ID

2 个答案: