Question

[比较两列ftp_start_time和ftp_stop_time并根据条件返回列数：3列为1.Tried（count（ftp_start_time））2。成功（非空时计数ftp_start_time和ftp_stop_time）3。失败（计数） ftp_stop_time必须为null）..请帮忙

Screenshot

SELECT 
    a.Branch_code,
    b.DevCount AS total,
    COUNT(a.ftp_start_time) AS tried
FROM 
    ftplogview AS a
LEFT JOIN 
    palmtecsetup AS b ON a.Branch_code = b.Branch_code
WHERE 
    ftp_start_date = '2016-03-31'
GROUP BY 
    a.Branch_code, b.DevCount
ORDER BY 
    Branch_code

这是我到目前为止使用的查询...任何人都可以帮助我吗？

Answer 1

我会使用公用表表达式

with cte(Branch_code, DevCount, total,ftp_start_time,ftp_stop_date,ftp_stop_time ) 
as (
SELECT 
    a.Branch_code,
    b.DevCount,
    a.ftp_start_time,
    a.ftp_stop_date,
    a.ftp_stop_time
FROM 
    ftplogview AS a
LEFT JOIN 
    palmtecsetup AS b ON a.Branch_code = b.Branch_code
GROUP BY 
    a.Branch_code, b.DevCount
 )
 SELECT  Branch_code,
    DevCount AS total,
    COUNT(ftp_start_time) AS tried,
    SUM(
    case  
       when ftp_start_time  is not null and  ftp_stop_time is not null then 1
       else 0 end
       ) as success,
    SUM(
       case  
          when ftp_stop_time is null then 1
          else 0 end
          ) as failed
 FROM CTE
 WHERE ftp_start_time =  '2016-03-31'

Answer 2

希望这个会帮助你，使用下面的子选择查询 -

    SELECT 
        q.Branch_code,
        q.DevCount AS total,
        COUNT(q.ftp_start_time) AS tried,
        SUM(Success) AS SuccessCount,
        SUM(Failed) AS FailedCount,
        SUM(NOTTRIED) AS NOTTRIEDCount
    FROM
    (
        SELECT
            a.Branch_code,
            b.DevCount AS total,
            a.ftp_start_time AS tried,
            CASE WHEN a.ftp_start_time IS NOT NULL AND a.ftp_stop_time IS NOT NULL THEN 1 ELSE 0 END AS Success,
            CASE WHEN a.ftp_start_time IS NOT NULL AND a.ftp_stop_time IS NULL THEN 1 ELSE 0 END AS Failed,
            CASE WHEN a.ftp_start_time IS NULL AND a.ftp_stop_time IS NULL THEN 1 ELSE 0 END AS NOTTRIED
        FROM 
            ftplogview AS a
        LEFT JOIN 
            palmtecsetup AS b ON a.Branch_code = b.Branch_code
        WHERE 
            ftp_start_date = '2016-03-31'    

    ) Q
    GROUP BY 
        Q.Branch_code, Q.Total
    ORDER BY 
        Q.Branch_code

比较两列ftp_start_time和ftp_stop_time，并根据条件返回列数

2 个答案: