如何将此数组转换为JavaScript对象?

时间:2016-03-31 09:00:35

标签: javascript

以下代码循环遍历JavaScript对象,并仅收集数组的属性:

const building = this.building
let panoramaList = []
for (let key in building) {
  const panoramas = building[key]
  if (Array.isArray(panoramas)) {
    panoramaList.push({ [key]: panoramas })
  }
}
console.log(panoramaList)

换句话说,它需要:

{
  name: '',
  description: ''.
  livingroom: Array[0],
  study: Array[1],
  bedroom: Array[0]
}

并将其变为:

[
  { livingroom: Array[0] },
  { study: Array[1] },
  { bedroom: Array[0] }
]

然而,我需要制作的是:

{
  livingroom: Array[0],
  study: Array[1],
  bedroom: Array[0]
}

如何做到这一点?

5 个答案:

答案 0 :(得分:1)

试试这个

var output = Object.keys(building).map(function(val){ return { val : building[val] } });

最终输出

var panoramaList = {}
Object.keys(building).forEach(function(val){ 
  if ( Array.isArray(building[val] )
  {
    panoramaList[val] = building[val];
  }
});

答案 1 :(得分:1)

改变这个:

const building = this.building
let panoramaList = []
for (let key in building) {
  const panoramas = building[key]
  if (Array.isArray(panoramas)) {
    panoramaList.push({ [key]: panoramas })
  }
}
console.log(panoramaList)

到此:

const building = this.building
let panoramaList = {}
for (let key in building) {
  const panoramas = building[key]
  if (Array.isArray(panoramas)) {
    panoramaList[key]=panoramas
  }
}
console.log(panoramaList)

答案 2 :(得分:1)

使用Object.keys并尝试这样的事情:

var input = {} //...your input array
var keys = Object.keys(input);
var result = {};

keys.forEach(function (key) {
    if (Array.isArray(input[key])) {
        result[key] = input[key];
    }
});

答案 3 :(得分:0)

确保将panoramaList定义为对象。

这有效

var arrays = {
  name: '',
  description: '',
  livingroom: ['1','www'],
  study: ['2','sss'],
  bedroom: ['3','aaa'],
  Kitchen: ['4','bbb'],
}    


const building = arrays
let panoramaList = {};
for (let key in building) {
  const panoramas = building[key]

  if (Array.isArray(panoramas)) {
      panoramaList[key] = panoramas;
  }
}
console.log(panoramaList);

https://jsbin.com/paqebupiva/1/edit?js,console,output

答案 4 :(得分:0)

您可能只需要从您拥有的对象中删除不需要的属性,而不是构建新对象:



var data = {
  name: '',
  description: '',
  livingroom: [],
  study: [1],
  bedroom: [0]
};

Object.keys(data).forEach(function(key) {
  if (!Array.isArray(data[key])) delete data[key];
})

document.write(JSON.stringify(data));