Question

我是asp MVC的新手，所以我会尝试使用ajax创建一个登录表单，所以我写了jsonresult来检查控制器中的用户名和密码，我在ajax中调用它但是它不工作并且我不知道为什么这样我的控制器代码

 public ActionResult login()
    {
        return View();
    }


    [HttpPost]

    public JsonResult ValidateUser(string username,string password)
    {
        using(var contxt=new EnglisCenterEntities())
        {
            var data = from a in contxt.Employee
                       where a.Username == username && a.Passwords == password
                       select a;
            if(data.Count()>0)
            {
                return Json(new { Success = true }, JsonRequestBehavior.AllowGet);
            }
            else
            {
                return Json(new { Success = false }, JsonRequestBehavior.AllowGet);
            }
        }
    }

这是我的观点和ajax代码

 <div class="container">
      <div class="row">
    <div class="col-md-6 col-md-offset-3 alert alert-warning">
        <h2 class="text-center">Login</h2>
        <div class="row">
            <div class="col-md-12">
                <div class="form-group">
                    <div class="input-group">
                        <span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span>
                        <input type="text" id="username" class="form-control" placeholder="Username">
                    </div>
                </div>
            </div>
        </div>
        <div class="row">
            <div class="col-md-12">
                <div class="form-group">
                    <div class="input-group">
                        <span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span>
                        <input type="password" class="form-control" id="password" placeholder="Password">
                    </div>
                </div>
            </div>
        </div>
        <div class="row">
            <div class="col-md-12">
                <div class="form-group">
                    <button class="btn btn-warning form-control" type="submit" id="savedata"><i class="glyphicon glyphicon-log-in"></i>&nbsp;Login</button>
                </div>

            </div>
        </div>
    </div>
</div>

           <script>
                   $(document).ready(function () {
                       $('#savedata').click(function () {
                           var data = {
                               "username": $("#username").val(),
                               "password": $("#password").val()
                           };
                           $.ajax({
                               url: "/Account/ValidateUser",
                               type: "Post",
                               data: JSON.stringify(data),
                               dataType: "json",
                               contentType: "application/json",
                               success: function (response) {
                                   if (response.Success) {
                                       $.get("@Url.Action("Index", "Home")", function (data) {
                                           $('.container').html(data);
                                       });

                                   }
                                   else
                                       window.location.href = "@Url.Action("Login", "Account")";
                               },
                               error: function () {
                                   console.log('Login Fail!!!');
                               }
                           });
                       });
                   });
         </script>

为什么它不起作用？任何帮助，请

Answer 1

不需要JSON.stringify，修改您的ajax电话data，如下所示： -

$.ajax({
          url: "/Account/ValidateUser",
          type: "Post",
          data: data,
          dataType: "json",
          .....
});

为什么ajax代码不起作用？

1 个答案: