Question

我正在做一个学校项目，我有点受阻。我期待构建一个javascript，询问用户1到20之间的数字，然后查找并列出该数字在0和100范围内的所有倍数。

目前看来是这样的：

public static void main(String[] args) {
    Scanner lector = new Scanner(System.in);
    System.out.println("*** Program start ***\n");
    System.out.println("Insert number [integer, between 1 and 20]: ");
    boolean okay = false;

    while (!okay) {
        int n1 = lector.nextInt();
        lector.nextLine();
        if (n1<1 || n1>20) {
            System.out.print("Invalid number!\nplease try again [between 1 and 20]: ");
        } else {
            okay = true;
            System.out.println("Number accepted!");
        }

    int i = 0;
    while (i <= 100) {
       System.out.println(i);

       if ((n1%100) == 0) {
           System.out.println(n1);
       }
       i = i + 1;
    }
    System.out.println("\n*** End ***");
    }
    }
}

我显然很擅长数学，因为我无法使公式发挥作用。

提前谢谢！

Answer 1

public static void main(String[] args) {
    Scanner lector = new Scanner(System.in);
    System.out.println("*** Program start ***\n");
    System.out.println("Insert number [integer, between 1 and 20]: ");
    boolean okay = false;

    while (!okay) {
        int n1 = lector.nextInt();
        lector.nextLine();
        if (n1<1 || n1>20) {
            System.out.print("Invalid number!\nplease try again [between 1 and 20]: ");
        } else {
            okay = true;
            System.out.println("Number accepted!");
        }

    int i = 0;
    while (i <= 100) {
       System.out.println(i);

       if ((n1%i) == 0) {
           System.out.println(i);
       }
       i = i + 1;
    }
    System.out.println("\n*** End ***");
    }
    }
}

Answer 2

public static void main(String[] args) {
    Scanner lector = new Scanner(System.in);
    System.out.println("*** Program start ***\n");
    System.out.println("Insert number [integer, between 1 and 20]: ");
    boolean okay = false;

    while (!okay) {
        int n1 = lector.nextInt();
        lector.nextLine();
        if (n1<1 || n1>20) {
            System.out.print("Invalid number!\nplease try again [between 1 and 20]: ");
        } else {
            okay = true;
            System.out.println("Number accepted!");
        }

    int i = 0;
    while (i <= 100) {
       System.out.println(i);

       if ((n1*i) <= 100) {
           System.out.println(i);
       }
       i = i + 1;
    }
    System.out.println("\n*** End ***");
    }
    }
}

这应该有效。您只是发现数字n1是否可以被100整除。

Answer 3

所有倍数介于0和100之间？这就是for-loops的用途。执行IO并读取数字n1后，将while循环更改为以下内容。

for (int i = n1; i >= 0 && i <= 100; i = i + n1) {
    System.out.println(i);
}

如果你不熟悉for循环，这基本上说，将i设置为n1的值，并继续向其添加n1，打印每个值当你去时。当它离开0..100的范围时，它终止。因此，例如，如果输入8，则为8,16,24,32，...，80,88,96。

如果您真的想使用while循环，请尝试：

int i = n1;
while(i >= 0 && i <= 100) {
    System.out.println(i);
    i = i + n1;
}

内部范围内的整数倍数

3 个答案: