迭代JSON格式的对象数组并修改和扩展它,最好使用Underscore.js

时间:2016-03-30 04:16:28

标签: javascript arrays json iterator underscore.js

我从JSON格式的数据库中检索数据,并将其分配给变量 - ' var tabs'。

格式化的JSON如下:

[{
    "TAB_ID": "1",
    "TAB_NAME": "TAB ONE",
    "TAB_DISPLAY": "1",
    "QUESTIONS": [{
        "QUESTION_ID": 1,
        "QUESTION": "Question number one",
        "ANSWER": ""
    }, {
        "QUESTION_ID": 2,
        "QUESTION": "Question number two",
        "ANSWER": ""
    }, {
        "QUESTION_ID": 3,
        "QUESTION": "Question number six",
        "ANSWER": ""
    }]
}, {
    "TAB_ID": "1",
    "TAB_NAME": "TAB ONE",
    "TAB_DISPLAY": "1",
    "QUESTIONS": [{
        "QUESTION_ID": 1,
        "QUESTION": "Question number one",
        "ANSWER": "Some Other Answer"
    }, {
        "QUESTION_ID": 2,
        "QUESTION": "Question number two",
        "ANSWER": ""
    }, {
        "QUESTION_ID": 3,
        "QUESTION": "Question number six",
        "ANSWER": "Some Still Different Answer"
    }]
}]

我需要迭代数组并执行以下操作:

对于TAB中的每个QUESTION,如果QUESTION有答案,我需要添加一个额外的键/值" HAS_ANSWER":" 1"问题。

    {
        "QUESTION_ID": 1,
        "QUESTION": "Question number one",
        "ANSWER": "Some Other Answer",
        "HAS_ANSWER": "1"
    }

我花了好几个小时阅读帖子,查看示例代码和阅读Underscore文档,我知道这应该相当简单,但我无法理解如何处理这个问题。

我的理解是我可能想要使用嵌套的_.map函数,但我所看到的所有示例都返回了对象数组的子集,而不是修改后的扩展,我需要最终得到完全相同的格式化JSON数据(对象数组),但上面提到的更改和添加。

非常感谢任何帮助。

更新

使用此:

data = _.map(data, obj => _.map(obj.QUESTIONS, q => {
    if (q.ANSWER) {
        q.HAS_ANSWER = 1;
    }
    return q;
}));

这会迭代问题,并相应地修改它们,但返回的对象会丢弃外层数据 - 它只返回一组问题,并且不会保留TAB数据:

    "TAB_ID": "1",
    "TAB_NAME": "TAB ONE",
    "TAB_DISPLAY": "1",

解决方案是在外部数组上使用_.each,在内部数组上使用_.map。

data = _.each(data, obj => _.map(obj.QUESTIONS, q => {
    if (q.ANSWER) {
        q.HAS_ANSWER = 1;
    }
    return q;
}));

注意:这=>语法仅适用于Javascript的较新实现,并且目前在Safari / Webkit中不受支持,因此请使用此语法以获得更好的兼容性

data = _.each(data, function(obj){
    _.map(obj.QUESTIONS, function(q){
       if (q.ANSWER) {
           q.HAS_ANSWER = 1;
       }
       return q;
    });
});

这完全按我需要的方式处理事情。

2 个答案:

答案 0 :(得分:1)

这可以使用普通的JavaScript,使用Array#map

来完成
// Iterate over data
data = data.map(obj => obj.QUESTIONS.map(q => {
    // If question has answer, then add `HAS_ANSWER` property
    if (q.ANSWER) {
        q.HAS_ANSWER = 1;
    }

    // Update question object
    return q;
}));

var data = [{
    "TAB_ID": "1",
    "TAB_NAME": "TAB ONE",
    "TAB_DISPLAY": "1",
    "QUESTIONS": [{
        "QUESTION_ID": 1,
        "QUESTION": "Question number one",
        "ANSWER": ""
    }, {
        "QUESTION_ID": 2,
        "QUESTION": "Question number two",
        "ANSWER": ""
    }, {
        "QUESTION_ID": 3,
        "QUESTION": "Question number six",
        "ANSWER": ""
    }]
}, {
    "TAB_ID": "1",
    "TAB_NAME": "TAB ONE",
    "TAB_DISPLAY": "1",
    "QUESTIONS": [{
        "QUESTION_ID": 1,
        "QUESTION": "Question number one",
        "ANSWER": "Some Other Answer"
    }, {
        "QUESTION_ID": 2,
        "QUESTION": "Question number two",
        "ANSWER": ""
    }, {
        "QUESTION_ID": 3,
        "QUESTION": "Question number six",
        "ANSWER": "Some Still Different Answer"
    }]
}];

data = data.map(obj => obj.QUESTIONS.map(q => {
    if (q.ANSWER) {
        q.HAS_ANSWER = 1;
    }
    return q;
}));

console.log(data);
document.getElementById('output').innerHTML = JSON.stringify(data, 0, 4);
<pre id="output"></pre>

Underscore / Lodash中的相同代码

data = _.map(data, obj => _.map(obj.QUESTIONS, q => {
    if (q.ANSWER) {
        q.HAS_ANSWER = 1;
    }
    return q;
}));

答案 1 :(得分:1)

使用标准的Javascript&#39; Array.prototype.forEach()方法,它看起来像这样:

% echo aaaj | awk '{gsub(/a*|j/,"x");print}'
xx

&#13;
&#13;
tabs.forEach(tab => {
  tab['QUESTIONS'].forEach(question => {
    if (question['ANSWER']) {
      question['HAS_ANSWER'] = 1;
    }
  });
});
&#13;
&#13;
&#13;

这种方法可以修改数据。