Question

假设我有对象数组，

[{"month":"03-2016","isLate":"N","transactionCount":4,"transactionAmount":8746455},{"month":"05-2016","isLate":"N","transactionCount":5,"transactionAmount":-40004952945.61},{"month":"06-2016","isLate":"N","transactionCount":1,"transactionAmount":100000},{"month":"04-2016","isLate":"N","transactionCount":6,"transactionAmount":-117189.89},{"month":"02-2016","isLate":"N","transactionCount":4,"transactionAmount":-5331000},{"month":"04-2016","isLate":null,"transactionCount":2,"transactionAmount":-4888.89},{"month":"03-2016","isLate":null,"transactionCount":3,"transactionAmount":5000}]

在下划线或javascript中有一个函数，我可以根据某些条件循环该项，删除某些对象，否则修改对象（在对象中添加更多信息）并返回数据。

Answer 1

您可以使用纯JavaScript：

删除某些对象：使用filter()
修改对象（将更多信息添加到对象中）：使用map()

例如：

var input = [
  {
    "month": "03-2016",
    "isLate": "N",
    "transactionCount": 4,
    "transactionAmount": 8746455
  },
  {
    "month": "05-2016",
    "isLate": "N",
    "transactionCount": 5,
    "transactionAmount": -40004952945.61
  },
  {
    "month": "06-2016",
    "isLate": "N",
    "transactionCount": 1,
    "transactionAmount": 100000
  },
  {
    "month": "04-2016",
    "isLate": "N",
    "transactionCount": 6,
    "transactionAmount": -117189.89
  },
  {
    "month": "02-2016",
    "isLate": "N",
    "transactionCount": 4,
    "transactionAmount": -5331000
  },
  {
    "month": "04-2016",
    "isLate": null,
    "transactionCount": 2,
    "transactionAmount": -4888.89
  },
  {
    "month": "03-2016",
    "isLate": null,
    "transactionCount": 3,
    "transactionAmount": 5000
  }
];

// Helper array to translate month number to month name 
var monthNames = ["January", "February", "March", "April", "May", "June",
  "July", "August", "September", "October", "November", "December"
];

input = input
    // only get the entries which don't have isLate=N:
    .filter( o => o.isLate !== 'N' )
    // add a property "mm":
    .map( o => Object.assign(o, { mm: monthNames[+o.month.substr(0,2)-1] }) );

// Output result
console.log(input);

对于没有ES6支持的JavaScript环境，请将input =语句替换为：

input = input
    // only get the entries which don't have isLate=N:
    .filter( function (o) {
        return o.isLate !== 'N'; 
    })
    // add a property "mm":
    .map( function (o) {
        o.mm = monthNames[+o.month.substr(0,2)-1];
        return o;
    });

Answer 2

是的，使用filter（）

var resArray = myArray.filter(x => x.transactionCount != 1);

在这个例子中，我删除了属性为transactionCount === 1

的元素

对象数组的下划线循环修改某些对象并删除一些对象

2 个答案: