如果调用HttpURLConnection，则为未处理的异常

Question

public  int coderesult (String urlstring) throws Exception {
    URL url = new URL(urlstring);
    HttpURLConnection httpCon = (HttpURLConnection) url.openConnection();
    //System.out.println("Response code is " + httpCon.getResponseCode());
    int mycode = httpCon.getResponseCode();
    return mycode;
}
public int displaycode () {
    int dispcode = 0;
    try {
        dispcode = coderesult(myurl);

    }
    catch (MalformedURLException e){
        e.printStackTrace();
    }catch(IOException e){
        e.printStackTrace();
    }finally {
    }
    return dispcode;
}    

Android Studio在“dispcode = coderesult（myurl）;”中显示错误：“未处理的异常：java.lang.Exception”

Answer 1

您的codeResult()方法会抛出Exception

public  int coderesult (String urlstring) throws Exception {

因此，您必须专门捕捉catch(Exception ex)，或声明您从方法中抛出它。

捕获异常时，您要么捕获特定的异常类型，要么捕获更通用的父异常类型。您可以将所有捕获组合成一个catch，因为所有内置的Java异常都从Exception扩展

catch(Exception ex){
    ex.printStackTrace();
}

Answer 2

使用此

public  int coderesult (String urlstring) throws IOException

并写

catch(IOException ie) {
            ie.printStackTrace();
}