Question

我正在尝试根据匹配的列数来排序搜索结果。

变量:Name，:Email和:Fullnumbers在PHP之前和之后获得％。

当我省略ORDER BY子句时，查询工作正常。当我从ORDER BY子句中删除Fullnumbers时，它也有效。名称和电子邮件部分匹配的行将按正确的顺序返回。但是，当包含Fullnumbers时，不会返回任何行。

为什么会这样，我该如何解决这个问题？

SELECT SQL_CALC_FOUND_ROWS DISTINCT(User.UserId), Name, Email,
GROUP_CONCAT(CONCAT(Countrycode, Number)) AS Fullnumbers
FROM User LEFT JOIN UserPhonenumber ON User.UserId = UserPhonenumber.UserId
GROUP BY UserId HAVING Name LIKE :Name OR Email LIKE :Email OR Fullnumbers LIKE :Fullnumbers
ORDER BY ((Name LIKE :Name) + (Email LIKE :Email) + (Fullnumbers LIKE :Fullnumbers)) DESC

Answer 1

然后，您想要使用ORDER BY CASE子句。这是一个例子：

ORDER BY CASE
  WHEN Name LIKE :Name THEN 1
  WHEN Email LIKE :Email THEN 2
  WHEN Fullnumbers LIKE :Fullnumbers THEN 3
  ELSE 4 END;

修改

使用多个IF子句，您可以按相关性排序结果集。

ORDER BY IF (Name LIKE :Name,1,0) + IF (Email LIKE :Email,1,0) + IF (Fullnumbers LIKE :Fullnumbers,1,0) DESC;

参考：MySQL order by relevance

编辑2 解决方案：

SELECT * FROM ( SELECT SQL_CALC_FOUND_ROWS DISTINCT(User.UserId), Name, Email, GROUP_CONCAT(CONCAT(Countrycode, Number)) AS Fullnumbers FROM User LEFT JOIN UserPhonenumber ON User.UserId = UserPhonenumber.UserId GROUP BY UserId HAVING Name LIKE :Name OR Email LIKE :Email OR Fullnumbers LIKE :Fullnumbers) AS t1 ORDER BY IF (Name LIKE :Name,1,0) + IF (Email LIKE :Email,1,0) + IF (Fullnumbers LIKE :Fullnumbers,1,0) DESC;

使用GROUP_CONCAT时，如何按照匹配的字段数排序行？

1 个答案: