Question

我试图在视图中创建一个总和，该总和是根据另一个列除以与ID匹配的行数计算得出的。例：总计=表1 /（ROWS，其中ID =相同）

到目前为止的观点是：

Create View testview AS (
  SELECT t2.ID,t1.Sum1 FROM
  Table1 t1
  LEFT JOIN
  Table2 t2
  ON
  t1.ID = t2.ID
);

下面是一个表格示例：

+-------+---------+--------+
| T2.ID | T1.Sum1 | Total  |
+-------+---------+--------+
|     1 | 10.00   | 10.00  |
|     2 | 15.00   | 15.00  |
|     3 | 20.00   | 10.00  |
|     3 | 20.00   | 10.00  |
|     4 | 30.00   | 10.00  |
|     4 | 30.00   | 10.00  |
|     4 | 30.00   | 10.00  |
+-------+---------+--------+

谢谢

Answer 1

试试这个。将Aggregate count与Window function一起使用，可以计算每个sum1中ID的数量，并使用它来划分sum1

CREATE TABLE #sum
  (
     ID   INT,
     Sum1 NUMERIC(4, 2)
  )

INSERT #sum
VALUES (1,10.00 ),
       (2,15.00 ),
       (3,20.00 ),
       (3,20.00 ),
       (4,30.00 ),
       (4,30.00 ),
       (4,30.00 )

SELECT *,
       Sum1 / Count(id)
                OVER (
                  partition BY id) AS Total
FROM   #sum

查看应该是这样的。

CREATE VIEW testview
AS
  (SELECT t2.ID,
          t1.Sum1,
          t1.Sum1 / Count(t2.id)OVER (partition BY id) AS Total
   FROM   Table1 t1
          LEFT JOIN Table2 t2
                 ON t1.ID = t2.ID);

除以ID匹配的行数

1 个答案: