将字典列表中的值添加到单独的列表中，并查找/计算常用值

Question

我有一个包含这样字典的列表：

[{"abc":"da123-tap","efg":"xyzf","acd":"123-brf"}, {"abc":"ab234-tap","efg":"yuvi","acd":"345-brf"}]  

我希望列表中的abc的所有值（list1）和efg的所有值都列在另一个列表中（list2）。

更新问题：

我读了一个文件来获取这个词典列表：

[{"Sample":"da123-tap","Name":"john","dof":"Date(304239600000)","Account":"Clinic1"},
{"Sample":"da456-tap-tap","Name":"smith","dof":"Date(304239600000)","Account":"Clinic2"},
{"Sample":"da678-tap-tap","Name":"jane","dof":"Date(304239600000)","Account":"Clinic1"},
{"Sample":"da987-tap-tap","Name":"doe","dof":"Date(304239600000)","Account":"Clinic2"}]

查找

1. Sample
中list1的值
2. Account
中list2的值
3. 计算属于Sample
的Clinic1的值
4. 计算属于Sample
的Clinic2的值

Answer 1

仅出于教育原因，将不同键的值导入多个列表的优雅方法可能是使用zip()并解压缩：

>>> l = [
...     {"abc":"da123-tap","efg":"xyzf","acd":"123-brf"}, 
...     {"abc":"ab234-tap","efg":"yuvi","acd":"345-brf"}
... ]
>>> 
>>> a, b = zip(*[(item["abc"], item["efg"]) for item in l])
>>> print(a)
('da123-tap', 'ab234-tap')
>>> print(b)
('xyzf', 'yuvi')