Question

我在python中有一个压缩任务来开发代码，如果输入是

'hello its me, hello can you hear me, hello are you listening'

然后输出应为

1,2,3,1,4,5,6,3,1,7,5,8

基本上每个单词都分配了一个数值，如果单词重复，那么这个单词也是如此。这个编码是在python中，请帮帮我谢谢

Answer 1

一种简单的方法是使用dict，当你发现一个新单词时使用递增变量添加一个键/值配对，当你看到这个单词之前只打印dict中的值：

/01/

输出：

s = 'hello its me, hello can you hear me, hello are you listening'


def cyc(s):
    # set i to 1 
    i = 1
    # split into words on whitespace
    it = s.split()
    # create first key/value pair 
    seen = {it[0]: i}
    # yield 1 for first word
    yield i
    # for all var the first word
    for word in it[1:]:
        # if we have seen this word already, use it's value from our dict
        if word in seen:
            yield seen[word]
        # else first time seeing it so increment count
        # and create new k/v pairing
        else:
            i += 1
            yield i
            seen[word] = i


print(list(cyc(s)))

您还可以使用[1, 2, 3, 1, 4, 5, 6, 3, 1, 7, 5, 8]并调用iter来弹出第一个单词来避免切片，如果您想要next我们需要删除字符串中的任何标点符号完成 str.rstrip ：

foo == foo!

Answer 2

如何使用item：index mapping：

构建dict

>>> s
'hello its me, hello can you hear me, hello are you listening'
>>> 
>>> l = s.split()
>>> d = {}
>>> i = 1
>>> for x in l:
        if x not in d:
            d[x]=i
            i += 1


>>> d
{'its': 2, 'listening': 8, 'hear': 6, 'hello': 1, 'are': 7, 'you': 5, 'me,': 3, 'can': 4}
>>> for x in l:
        print(x, d[x])


hello 1
its 2
me, 3
hello 1
can 4
you 5
hear 6
me, 3
hello 1
are 7
you 5
listening 8
>>>

如果您不希望拆分列表中出现任何标点符号，则可以执行以下操作：

>>> import re
>>> l = re.split(r'(?:,|\s)\s*', s)
>>> l
['hello', 'its', 'me', 'hello', 'can', 'you', 'hear', 'me', 'hello', 'are', 'you', 'listening']

Answer 3

import re
from collections import OrderedDict

text = 'hello its me, hello can you hear me, hello are you listening'
words = re.sub("[^\w]", " ",  text).split()
uniq_words = list(OrderedDict.fromkeys(words))
res = [uniq_words.index(w) + 1 for w in words]

print(res)  # [1, 2, 3, 1, 4, 5, 6, 3, 1, 7, 5, 8]

在python中为字符串中的单词分配数字

3 个答案: