将列表中的单词分配给每个单词之间带有空格的字符串

Question

我想将列表中的单词转换为空字符串，但我也需要将单词用空格分隔。不要粘在一起。

例如：

def list_to_string(words):
    sentence = ""
    for word in words:
        sentence = sentence + word
return sentence

测试：

list_to_string(["moo", "lee", "raa", "soo"])
'mooleeraasoo'

但是我要找的是每两个单词之间的空格字符：

'moo lee raa soo'

Answer 1

您可以使用单行join而不使用循环。

' '.join(["moo", "lee", "raa", "soo"])
'moo lee raa soo'

Answer 2

对于每次迭代，在单词中添加一个空格，最后在返回结果字符串时进行剥离。

def list_to_string(words):
    sentence = ""
    for word in words:
        sentence += word + " "
    return sentence.rstrip()     # before returning the string, this would strip all the trailing spaces.