用于Kaggle Titanic数据集的R中SVM调整的错误

Question

我尝试使用Titanic Kaggle数据集完成R中SVM模型的调整。

当我运行以下代码时：

tune.out = tune(svm, Survived ~ Pclass + Sex + Age + Fare + Embarked + family, 
            data = boat, kernel = "linear", 
            ranges = list(cost = c(0.001, 0.01, 0.1, 1, 5, 10, 100)))

我收到错误：

Error in names(ret2) <- rowns : 
 'names' attribute [90] must be the same length as the vector [71]

使用追溯：

3: predict.svm(model, if (!is.null(validation.x)) validation.x else if (useFormula) data[-train.ind[[sample]], 
   , drop = FALSE] else if (inherits(train.x, "matrix.csr")) train.x[-train.ind[[sample]], 
   ] else train.x[-train.ind[[sample]], , drop = FALSE])
2: predict.func(model, if (!is.null(validation.x)) validation.x else if (useFormula) data[-train.ind[[sample]], 
   , drop = FALSE] else if (inherits(train.x, "matrix.csr")) train.x[-train.ind[[sample]], 
   ] else train.x[-train.ind[[sample]], , drop = FALSE])
1: tune(svm, Survived ~ Pclass + Sex + Age + Fare + Embarked + family, 
   data = boat, kernel = "linear", ranges = list(cost = c(0.001, 
       0.01, 0.1, 1, 5, 10, 100)))

我明白我的变量可能有问题 - 可能是什么想法？

如果它有帮助，我还没有修改任何变量，但已经掉了一堆（调整公式中没有看到的那些变量，并通过以下方式创建了一个新变量family：

boat$family = boat$SibSp + boat$Parch
boat$family[boat$family > 0] = 1

船是data.table。