我是StackOverflow的新手,所以我不确定这是如何工作的,但我真的需要一些帮助,我正在Android Studio中构建这个应用程序。我有一个预先填充的chemicals.sqlite数据库,我试图在Android Studio中搜索。基本上,我正在设计的应用程序将允许用户按名称搜索化合物,它将显示有关它的信息。出于某种原因,我的程序说它无法显示我试图在应用程序的模拟器中搜索的任何值。它总是显示“找不到匹配”。
这是我的DatabaseHelper类:
import android.content.Context;
import android.database.Cursor;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;
public class DataBaseHelper extends SQLiteOpenHelper {
private static final int DATABASE_VERSION = 1;
private static final String DATABASE_NAME = "chemicals.sqlite";
private static final String TABLE_OSHA = "osha";
public static final String COLUMN_COMPOUND = "compound";
public static final String COLUMN_H = "h";
public static final String COLUMN_F = "f";
public static final String COLUMN_R = "r";
public static final String COLUMN_SN = "sn";
public DataBaseHelper(Context context, String name,
SQLiteDatabase.CursorFactory factory, int version) {
super(context, DATABASE_NAME, factory, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
String CREATE_OSHA_TABLE = "CREATE TABLE " +
TABLE_OSHA + "("
+ COLUMN_COMPOUND + " TEXT," + COLUMN_H
+ " TEXT," + COLUMN_F + " TEXT," + COLUMN_R + " TEXT," + COLUMN_SN + " TEXT" + ")";
db.execSQL(CREATE_OSHA_TABLE);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion,
int newVersion) {
db.execSQL("DROP TABLE IF EXISTS " + TABLE_OSHA);
onCreate(db);
}
public Compound findCompound(String compoundname) {
String query = "Select * FROM " + TABLE_OSHA + " WHERE " + COLUMN_COMPOUND + "= '" + compoundname + "'";
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(query, null);
Compound compound = new Compound();
if (cursor.moveToFirst()) {
cursor.moveToFirst();
compound.setH(cursor.getString(0));
compound.setF(cursor.getString(1));
compound.setR(cursor.getString(2));
compound.setSN(cursor.getString(3));
// cursor.moveToNext();
cursor.close();
} else {
compound = null;
}
db.close();
return compound;
}
}
这是我的复合课:
public class Compound {
private String _compound;
private String _h;
private String _f;
private String _r;
private String _sn;
public Compound() {
}
public Compound(String compound, String h, String f, String r, String sn) {
this._compound = compound;
this._h = h;
this._f = f;
this._r = r;
this._sn = sn;
}
public Compound(String h, String f, String r, String sn) {
this._h = h;
this._f = f;
this._r = r;
this._sn = sn;
}
public void setCompound(String compound) {
this._compound = compound;
}
public String getCompound() {
return this._compound;
}
public void setH(String h) {
this._h = h;
}
public String getH() {
return this._h;
}
public void setF(String f) {
this._f = f;
}
public String getF() {
return this._f;
}
public void setR(String r) {
this._r = r;
}
public String getR(){
return this._r;
}
public void setSN(String sn){
this._sn = sn;
}
public String getSN(){
return this._sn;
}
}
这是我的主要课程:
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
public class oshaSearch extends AppCompatActivity {
TextView txtH;
TextView txtR;
TextView txtF;
TextView txtSN;
EditText txtCompound;
Button btnSearch;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_osha_search);
txtF = (TextView) findViewById(R.id.txtF);
txtR = (TextView) findViewById(R.id.txtR);
txtH = (TextView) findViewById(R.id.txtH);
txtSN = (TextView) findViewById(R.id.txtSN);
txtCompound = (EditText) findViewById(R.id.searchCompound);
btnSearch = (Button) findViewById(R.id.btnSearch);
}
public void lookupCompound (View view) {
DataBaseHelper dbHandler = new DataBaseHelper(this, null, null, 1);
Compound compound =
dbHandler.findCompound(txtCompound.getText().toString());
if (compound != null) {
txtH.setText(String.valueOf(compound.getH()));
txtF.setText(String.valueOf(compound.getF()));
txtR.setText(String.valueOf(compound.getR()));
txtSN.setText(String.valueOf(compound.getSN()));
} else {
txtH.setText("No Match Found");
}
}
}
非常感谢任何和所有帮助。请帮帮我。 附加信息:数据库位于assets文件夹中,数据库中的所有值都是文本字段,用户按复合名称搜索,数据库具有.sqlite扩展名。谢谢大家。
答案 0 :(得分:0)
您必须将您在资产文件夹中所说的数据库复制到新创建的数据库 -
private void copyDataBase(String dbname) throws IOException {
// Open your local db as the input stream
InputStream myInput = myContext.getAssets().open(dbname);
// Path to the just created empty db
String outFileName = getDatabasePath(dbname);
// Open the empty db as the output stream
OutputStream myOutput = new FileOutputStream(outFileName);
// transfer bytes from the inputfile to the outputfile
byte[] buffer = new byte[1024];
int length;
while ((length = myInput.read(buffer)) > 0) {
myOutput.write(buffer, 0, length);
}
// Close the streams
myOutput.flush();
myOutput.close();
myInput.close();
}
答案 1 :(得分:0)
首先需要检查是否正确创建了数据库
public DataBaseHelper(Context context) {
super(context, Environment.getExternalStorageDirectory()+"/"+DATABASE_NAME, null, 1);
}
使用此构造函数,这会将您的应用数据库保存在手机的外部存储中。 之前,在清单文件中授予外部存储权限。 并使用google play store中的sqliteManager应用程序来检查数据库结构。
或者您可以使用stetho来调试android的数据库。 参考链接:http://code.tutsplus.com/tutorials/debugging-android-apps-with-facebooks-stetho--cms-24205