Question

如何在提交表单并且出现错误后填充并显示$errors变量？

<form method="post" action="<?php $_SERVER['PHP_SELF']; ?>">
  <?php
    if(!is_null($errors)) {
        echo "<h3>$errors</h3>";
    }
  ?>

  <label for="Name">Name</label><em>(Required)</em>
  <input type="text" name="Name"/>

  <label for="Email">Email</label><em>(Required)</em>
  <input type="text" name="Email"/>

  <label for="Website">Website</label>
  <input type="text" name="Website"/>

  <label for="Message">Message</label><em>(Required)</em>
  <textarea name="Message"></textarea>

  <button id="submit" type="submit" value="submit"name="submit">Submit</button>
  <input type="hidden" name="Submit" />
</form>

和我的脚本来处理表单

$errors = null;

if(isset($_POST['submit'])) {   

  if(!empty($_POST['Name']) && !empty($_POST['Email']) && !empty($_POST['Message'])) {

    $name = $_POST['Name'];
    $email = $_POST['Email'];
    $website = $_POST['Website'];
    $message = $_POST['Message'];

    //strip any html tags and slashes off of the fields
    $nameClean = strip_tags($name);
    $emailClean = strip_tags($email);
    $websiteClean = strip_tags($website);
    $messageClean = strip_tags($message);
    $messageCleanAndStripped = stripslashes($messageClean);
  }

} else {
    $errors = "Please fill in the required fields";
}

Answer 1

即使您第一次加载页面，也会显示

$ errors，因为这就是您的代码所做的事情：

if(isset($_POST['submit'])) 
{
  ....
} 
else 
{
    $errors = "Please fill in the required fields";
}

这意味着如果用户第一次加载页面，他没有发布任何内容，因此isset（$ _ POST ['submit']）为false，然后您将错误消息分配给$ errors变量。您应该将代码更改为：

if(isset($_POST['submit'])) {   

  if(!empty($_POST['Name']) && !empty($_POST['Email']) && !empty($_POST['Message'])) {

    $name = $_POST['Name'];
    $email = $_POST['Email'];
    $website = $_POST['Website'];
    $message = $_POST['Message'];

    //strip any html tags and slashes off of the fields
    $nameClean = strip_tags($name);
    $emailClean = strip_tags($email);
    $websiteClean = strip_tags($website);
    $messageClean = strip_tags($message);
    $messageCleanAndStripped = stripslashes($messageClean);
  }
  else 
  {
    $errors = "Please fill in the required fields";
  }

}

只需在条件中插入else语句，这样只有在用户实际提交内容时才会检查错误。

希望它有所帮助。

Answer 2

你有if-else错误匹配。这样做：

if(isset($_POST['submit']))
{   
  if(!empty($_POST['Name']) && !empty($_POST['Email']) && !empty($_POST['Message']))
  {
    $name = $_POST['Name'];
    $email = $_POST['Email'];
    $website = $_POST['Website'];
    $message = $_POST['Message'];

    //strip any html tags and slashes off of the fields
    $nameClean = strip_tags($name);
    $emailClean = strip_tags($email);
    $websiteClean = strip_tags($website);
    $messageClean = strip_tags($message);
    $messageCleanAndStripped = stripslashes($messageClean);
  }
  else
  {
      $errors = "Please fill in the required fields";
  }
}

如何显示表单验证错误？

2 个答案: