Question

我想知道如何在函数validate（）中显示我的模型中的错误消息，当提交不是“有效”时返回“无效的用户名或密码”

index.scala.html

@(myForm: Form[models.profile.MUser])

@import helper._
@import helper.twitterBootstrap._

@main("welcome") {

  <h1>Login with your account</h1>

@helper.form(action = routes.Application.loginAccount()) {

    @helper.inputText(myForm("username"),'_showConstraints -> false)
    @helper.inputPassword(myForm("password"),'_showConstraints -> false)

    <input type="submit" value="Login">
}}

Application.java

public static Result loginAccount() {
        Form<MUser> filledform = loginForm.bindFromRequest();
        if (filledform.hasErrors()) {
            Logger.debug("unsuccessfull loggin");
              return badRequest(index.render(filledform));
        }
        MUser user = filledform.get();
        SessionCache.setCache(SessionCache.Constants.LOGGED_IN_USER,
                UserController.findUserByUserName(user.username));
        return redirect("/home");

    }

MUser.java package models.profile;

import controllers.services.UserController;
import models.entities.UserDTO;
import play.data.validation.Constraints.*;
import scala.Serializable;

/**
 * @author fbranchetti
 * 
 */
public class MUser implements Serializable{

    @Required
    public String username;
    @Required
    public String password;


    public String validate() {
        if (authenticate(username, password)) {
            return "Invalid username or password";
        }
        return null;
    }


    private boolean authenticate(String username, String password) {
        UserDTO fUser = new UserDTO();
        fUser.setPassword(password);
        fUser.setUsername(username);

        return !UserController.logginUser(fUser);
    }

}

Answer 1

您可以将身份验证的结果存储在Flash变量中。在视图中，您可以检查变量是否存在并显示它。

如何显示表单验证错误

1 个答案: