Question

我有一个包含3列的表格，例如Food，Type和Taste。

列Food可以有任何内容
列Type可能有'Fruit'或'Vegetable'作为可能的值
列Taste可能包含'Bad'，'Good'或'Delicious'作为可能的值

我试图得到（到目前为止没有运气）一个SQL语句，它会产生一个像：

这样的表

            Bad       Good    Delicious   Total
Fruit        05         09           16      20
Vegetables   12         20           03      35
Total        17         29           19      55

输出表上的数字是每个Food / Type组合表格中Taste个数的COUNT。

如何实现？

Answer 1

前两行可以在一个带有子查询子句的查询中完成：

SELECT X."Type", 
       SUM(X."Bad") AS "Bad",
       SUM(X."Good") AS "Good",
       SUM(X."Delicious") AS "Delicious",
       SUM(X."Total") AS "Total" 
FROM (SELECT "Type",
          CASEWHEN("Taste" = 'Bad',1,0) AS "Bad",
          CASEWHEN("Taste" = 'Good',1,0) AS "Good",
          CASEWHEN("Taste" = 'Delicious',1,0) AS "Delicious",
          1 AS "Total" FROM "YourTableName") X 
GROUP BY "Type"

子查询创建列＆＃34; Bad＆＃34;，＆＃34; Good＆＃34;和＃34;美味＆＃34;如果每列中有1或0，则查询的外部会将所有值相加。

要获取底部的总计行，您必须使用Base解析器不支持的UNION ALL。要使此查询生效，您需要启用Edit→Run SQL Directly选项。（这将禁用某些需要解析器的表单和报表功能 - 它可能对您的使用无关紧要，但如果您稍后在表单或报表中使用此查询，则仅供参考。）

您UNION ALL的查询基本上是相同的查询，您只是不按类型分组。所以总计：

SELECT X."Type", 
       SUM(X."Bad") AS "Bad",
       SUM(X."Good") AS "Good",
       SUM(X."Delicious") AS "Delicious",
       SUM(X."Total") AS "Total" 
FROM (SELECT "Type",
          CASEWHEN("Taste" = 'Bad',1,0) AS "Bad",
          CASEWHEN("Taste" = 'Good',1,0) AS "Good",
          CASEWHEN("Taste" = 'Delicious',1,0) AS "Delicious",
          1 AS "Total" FROM "YourTableName") X 
GROUP BY "Type"

UNION ALL

SELECT 'Total' AS "BottomTotal",
       SUM(Y."Bad"),
       SUM(Y."Good"),
       SUM(Y."Delicious"),
       SUM(Y."Total") 
FROM (SELECT CASEWHEN("Taste" = 'Bad',1,0) AS "Bad",
          CASEWHEN("Taste" = 'Good',1,0) AS "Good",
          CASEWHEN("Taste" = 'Delicious',1,0) AS "Delicious",
          1 AS "Total" FROM "YourTableName") Y 
GROUP BY "BottomTotal"

确保替换＆＃34; YourTableName＆＃34;与您的实际表名一起。

LibreOffice Base - SQL查询的困难

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