Question

我目前正在为在线游戏开发拍卖网站。但是，在创建统计信息时，我遇到了查询问题。

问题是我需要参加我参加的所有拍卖以及我丢失的拍卖。但到目前为止，我只看到能够得到所有丢失的拍卖（不仅仅是我参与的拍卖）。

假设我有以下表格：

表拍卖的表格结构

CREATE TABLE IF NOT EXISTS `Auction` (
  `id` varchar(50) NOT NULL,
  `preferedAuctionId` varchar(50) NOT NULL,
  `winningTicketId` int(11) NOT NULL DEFAULT '-1',
  `createdOn` datetime NOT NULL,
  `startedOn` datetime NOT NULL,
  `finishedOn` datetime NOT NULL,
  `active` tinyint(1) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

-

- 表`AuctionBids`

的表结构

CREATE TABLE IF NOT EXISTS `AuctionBids` (
  `bidId` varchar(50) NOT NULL,
  `accountId` varchar(50) NOT NULL,
  `auctionId` varchar(50) NOT NULL,
  `ticketId` int(50) NOT NULL,
  `datetime` datetime NOT NULL,
  PRIMARY KEY (`bidId`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

以下是我尝试的一些查询。

SELECT * 
FROM Auction au, AuctionBids ab 
WHERE au.id = ab.auctionId AND au.winningTicketId = ab.ticketId AND 
      ab.accountId NOT LIKE '". $_accountId ."' AND 
      au.finishedOn NOT LIKE '0000-00-00 00:00:00' AND au.active = '0'

和

SELECT * 
FROM Auction 
WHERE winningTicketId NOT IN 
(    SELECT ticketId 
     FROM AuctionBids 
     WHERE accountId = '". $_accountId ."') 
   AND finishedOn NOT LIKE '0000-00-00 00:00:00' AND active = '0'

如果您遗漏了任何重要信息，请询问我，我会为您提供。

你的真诚， Larssy1

在您的localhost上测试我已经进行了测试转储：

http://pastebin.com/d412ESVa

预期结果：

accountId'{0D3FB1B2-1C0C-06EA-979A-15F5B5231E7C}的人赢得了他参与的所有拍卖，这意味着他返回的行应为0。

accountId'{65CC1576-C3C3-5AC1-8098-B8CF1347F481}'的人失去了他参与的所有拍卖，这意味着他返回的行应为1。

Answer 1

我认为你正在寻找一张联合表。我假设winsTicket字段包含获胜的票证ID。

SELECT * 
FROM Auction JOIN AuctionBids ON Auction.id=AuctionBids.auctionId
WHERE Auction.active=0 AND 
      AuctionBids.accountId=yourAccountID AND 
      Auction.winningTicket<>AuctionBids.ticketId

也许这会有所帮助或让你以正确的方式前进？

===更新===

如果你这样做怎么办：

SELECT 
    Auction.id AS auctionID,
    Auction.winningTicketId,
    SUM( IF(Auction.winningTicketId=AuctionBids.ticketId, IF(AuctionBids.accountId=yourID,1,0 ),0) ) AS youWON,
    SUM( IF(AuctionBids.accountId=yourID,1,0) ) AS nYouBID
FROM Auction JOIN AuctionBids ON Auction.id=AuctionBids.auctionId
WHERE
    Auction.active=0
GROUP BY Auction.id
ORDER BY youWON ASC, nYouBID DESC, auctionID ASC

将您的ID替换为“{0D3FB1B2-1C0C-06EA-979A-15F5B5231E7C}” SQLFiddle：http://sqlfiddle.com/#!2/dd8a9/15

如果你是实际出价的话，如果你是赢家的话，这将为每个非主动拍卖提供一行两个bool。然后，您必须解析第一行，直到遇到youWON == 1.

Answer 2

也许是这样？

SELECT distinct a.* FROM Auction a JOIN AuctionBids ab ON a.id = ab.auctionId 
WHERE a.winningTicketId not in 
(select ticketId from AuctionBids WHERE accountId = '". $_accountId ."'
and a.id = auctionId) 
AND a.id in
(select auctionId from AuctionBids WHERE accountId = '". $_accountId ."')
AND a.active = '0'
AND finishedOn NOT LIKE '0000-00-00 00:00:00';

编辑。在SQLFiddle

中试用

Answer 3

如果您想要它用于您的帐户ID，那么为什么您使用了ab.accountId NOT LIKE'“。$ _accountId。”'？

 I think you should use ab.accountId LIKE '". $_accountId ."'

Answer 4

像这样的东西，你可以检索'赢'，'输'，'参与'（未经测试，但方法是对的，我猜）

SELECT 'win', A.*, B,*
FROM Auction A INNER JOIN AuctionBids B
  ON A.id = B.auctionId
WHERE B.accountId = $me
  AND B.active = 0
  AND A.winningTicketId = B.bidID

UNION

SELECT 'lose', A.*, B,*
FROM Auction A INNER JOIN AuctionBids B
  ON A.id = B.auctionId
WHERE B.accountId = $me
  AND B.active = 0
  AND A.winningTicketId !=  B.bidID

UNION

SELECT 'ing', A.*, B,*
FROM Auction A INNER JOIN AuctionBids B
  ON A.id = B.auctionId
WHERE B.accountId = $me
  AND B.active = 1

与WHERE .. IN查询的困难

- 表`AuctionBids`

4 个答案:

与WHERE .. IN查询的困难

- 表AuctionBids

4 个答案:

- 表`AuctionBids`