Question

我希望在java代码中使用以下curl请求。我看到我们可以使用httpget来调用休息服务。

这是我的curl命令：

<xsd:element name="b" type="CT_OnOff" minOccurs="0">
  <xsd:annotation>
    <xsd:documentation>Bold</xsd:documentation>
  </xsd:annotation>
</xsd:element>

<xsd:complexType name="CT_OnOff">
  <xsd:attribute name="val" type="ST_OnOff">
    <xsd:annotation>
      <xsd:documentation>On/Off Value</xsd:documentation>
    </xsd:annotation>
  </xsd:attribute>
</xsd:complexType>

<xsd:simpleType name="ST_OnOff">
  <xsd:annotation>
    <xsd:documentation>On/Off Value</xsd:documentation>
  </xsd:annotation>
  <xsd:restriction base="xsd:string">
    <xsd:enumeration value="true">
      <xsd:annotation>
        <xsd:documentation>True</xsd:documentation>
      </xsd:annotation>
    </xsd:enumeration>
    <xsd:enumeration value="false">
      <xsd:annotation>
        <xsd:documentation>False</xsd:documentation>
      </xsd:annotation>
    </xsd:enumeration>
    <xsd:enumeration value="on">
      <xsd:annotation>
        <xsd:documentation>True</xsd:documentation>
      </xsd:annotation>
    </xsd:enumeration>
    <xsd:enumeration value="off">
      <xsd:annotation>
        <xsd:documentation>False</xsd:documentation>
      </xsd:annotation>
    </xsd:enumeration>
    <xsd:enumeration value="0">
      <xsd:annotation>
        <xsd:documentation>False</xsd:documentation>
      </xsd:annotation>
    </xsd:enumeration>
    <xsd:enumeration value="1">
      <xsd:annotation>
        <xsd:documentation>True</xsd:documentation>
      </xsd:annotation>
    </xsd:enumeration>
  </xsd:restriction>
</xsd:simpleType>

如何将该命令放入我的HttpGet curl -XGET 'localhost:9200/indexname/status/_search' -d '{"_source": {"include": [ "field1", "name1" ]}, "query" : {"term": { "Date" :"2000-12-23T10:12:05" }}}'

请指教。感谢。

Answer 1

组合-X GET and -d会导致您的数据以application / x-www-form-urlencoded格式附加到网址。

因此，我建议使用URLEncoder，如下所示：

String host = "localhost:9200/indexname/status/_search";
String data = "{\"_source\": {\"include\": [ \"field1\", \"name1\" ]}, \"query\" : {\"term\": { \"Date\" :\"2000-12-23T10:12:05\" }}}";
String url = host + "?" + URLEncoder.encode(data, "UTF-8");

Answer 2

您可以使用HttpURLConnection。 此代码是我认为适合您的示例：

public void get() throws IOException{
    //Create a URL object.
    String url = "localhost:9200/indexname/status/_search";
    URL getURL = new URL(url);

    //Establish a https connection with that URL.
    HttpsURLConnection con = (HttpsURLConnection) getURL.openConnection();

    //Select the request method, in this case GET.
    con.setRequestMethod("GET");

    con.setDoOutput(true);
    DataOutputStream wr = new DataOutputStream(con.getOutputStream());

    String parameters = "{\"_source\": {\"include\": [ \"field1\", \"name1\" ]}, \"query\" : {\"term\": { \"Date\" :\"2000-12-23T10:12:05\" }}}";

    //Write the parameter into the Output Stream, flush the data and then close the stream.
    wr.writeBytes(parameters);
    wr.flush();
    wr.close();

    System.out.println("\nSending 'GET' request to URL : " + url);
    int responseCode;
    try {
        responseCode = con.getResponseCode();
        System.out.println("Response Code : " + responseCode);
    } catch (Exception e) {
        System.out.println("Error: Connection problem.");
    }

    //Read the POST response.
    InputStreamReader isr = new InputStreamReader(con.getInputStream());
    BufferedReader br = new BufferedReader(isr);

    StringBuffer response = new StringBuffer();

    String inputLine;
    while ((inputLine = br.readLine()) != null) {
        //Save a line of the response.
        response.append(inputLine + '\n');
    }
    br.close();

    System.out.println(response.toString());
}

如果这不起作用，因为我必须对参数进行错误输入，无论如何都要尝试

将curl转换为httpGet

2 个答案: