Question

我的代码如下。我用httpPost写它，但我必须将它转换为httpGet。因为我们使用的webservice需要HttpGet。我怎样才能转换它并正确使用它。提前谢谢。

String nameValue = new String();
        HttpParams httpParameters = new BasicHttpParams();
        int timeoutConnection = 6000;
        HttpConnectionParams.setConnectionTimeout(httpParameters,
                timeoutConnection);
        int timeoutSocket = 6000;
        HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket);
        HttpClient httpclient = new DefaultHttpClient();

        httpPost httpget = new httpPost(
                "http://178.16.1.1:8080/Pets/REST/WebService/setUser");
        HttpResponse response;
        String result = null;
        try {

            HttpContext ctx = new BasicHttpContext();

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(
                    2);
            nameValuePairs.add(new BasicNameValuePair("username", username
                    .getText().toString()));
            nameValuePairs.add(new BasicNameValuePair("password", pasword
                    .getText().toString()));
            nameValuePairs.add(new BasicNameValuePair("email", username
                    .getText().toString()));
            nameValuePairs.add(new BasicNameValuePair("city", pasword
                    .getText().toString()));
            nameValuePairs.add(new BasicNameValuePair("county", username
                    .getText().toString()));
            nameValuePairs.add(new BasicNameValuePair("adress", pasword
                    .getText().toString()));
            httpget.setEntity(new UrlEncodedFormEntity(nameValuePairs,
                    "UTF-8"));

            response = httpclient.execute(httpget, ctx);
            HttpEntity resEntity = response.getEntity();

            if (resEntity != null) {
                result = EntityUtils.toString(resEntity);
                JSONObject arr = new JSONObject(result);

                nameValue = (arr.get("error")).toString();

            }
            return nameValue;

Answer 1

GET按照here

所述在网址http://178.16.1.1:8080/Pets/REST/WebService/setUser?username=username&password=password中发送参数

所以你应该像这样使用StringBuilder：

String[] parameters = new String[]{"username", "password"};
String[] values = new String[]{"username", "password"};
StringBuilder url = new StringBuilder(
                    "http://178.16.1.1:8080/Pets/REST/WebService/setUser");
url.append('?');
for (int i = 0; i < parameters.length; i++) {
    url.append(parameters[i]+"="+values[i]+"&");
}
url.deleteCharAt(url.length());
HttpGet httpget = new HttpGet(url.toString());

这将为HTTP GET

创建URL次来电

http://178.16.1.1:8080/Pets/REST/WebService/setUser?username=username&password=password

将HttpPost转换为HttpGet

1 个答案: