Question

我有一个计算开始日期和结束日期的函数。

然后打印出这段代码：

   $log.log("currentDate: " + currentDate);
   $log.log("currentDate: " + startDate + " " + (currentDate.valueOf() > startDate.valueOf()));
   $log.log("currentDate: " + endDate + " " + (currentDate.valueOf() < endDate.valueOf()));

但是在我的控制台窗口中，比较返回false，即使它们应该返回true！

currentDate: Fri Mar 18 2016 14:09:26 GMT-0500 (CDT)angular.js:12722 
currentDate: Fri Mar 18 2016 08:00:26 GMT-0500 (CDT) false
currentDate: Fri Mar 18 2016 19:30:26 GMT-0500 (CDT) false

我在这里做错了吗？

Answer 1

我没有关于你的变量的完整上下文，但我创建了一个plunker并且仅使用setTimeout按预期工作。请检查valueOf（）如何按预期工作并提供 true

var currentDate, endDate, startDate= new Date();

setTimeout(function(){
  currentDate = new Date();
}, 1000)
setTimeout(function(){
  endDate = new Date();
},2000)

setTimeout(function(){
  $log.log("currentDate: " + currentDate);
  $log.log("currentDate: " + startDate + " " + (currentDate.valueOf() > startDate.valueOf()));
  $log.log("currentDate: " + endDate + " " + (currentDate.valueOf() < endDate.valueOf()));
  $scope.message = 'Hello World!';
},3000);

Javascript日期比较奇怪的行为

1 个答案: